For this case we have the following equation:
w = || F || • || PQ || costheta
Where,
|| F ||: force vector module
|| PQ ||: distance module
costheta: cosine of the angle between the force vector and the distance vector.
Substituting values:
w = (60) * (100) * (cos (45))
w = 4242.640687 lb.ft
Answer:
The work done pushing the lawn mower is:
w = 4242.640687 lb.ft
Answer:
y = 7
Step-by-step explanation:
Solve for y:
7/y = 1
Take the reciprocal of both sides:
y/7 = 1
Multiply both sides by 7:
Answer: y = 7
Answer:
2 CH4(g) + 4 O2(g) --> 2 CO2 (g)+ 4 H2O(g)
Step-by-step explanation:
The number are subscripts.
Now count the number of each kind of atom on the left and right side of the equation. Note, you have 4 H on the left and as written you have only 2 on the right. So add a coefficient-- a number in front of the formula.
CH4 +O2 ----- CO2 + 2 H2O
With the added coefficient in front of water, the number of hydrogens balance but the number of oxygens do not. There are only 2 oxygens on the left and a total of 4 oxygens on the right. A coefficient of 2 in front of oxygen on the left balances the equation.
His claim is resonable 154/25=6 r4 6x2=12
Answer:
54 cm
Step-by-step explanation: 1/2b x h
1/2(18) x 6
9 x 6=54
