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Fofino [41]
2 years ago
14

Can some on help me please??

Mathematics
2 answers:
erma4kov [3.2K]2 years ago
5 0

Answer:

Frequency is 2, 2 and 3.

Step-by-step explanation:

Temp in 101 to 106 - In this range only 2 temperature is there 104 and 104 in 2 cities. so frequency is 2.

Temp in 107 to 112 - In this range only 2 temperature is there 107 and 112 in 2 cities. so frequency is 2.

Temp in 113 to 118 - In this range only 3 temperature is there 114, 117 and 118 so frequency is 3.

Bogdan [553]2 years ago
5 0
2, 2, and three

hoped that helped
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Is the following relation a function? (
PolarNik [594]
No, because there are TWO values of y for a certain value of x

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4 0
3 years ago
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PLEASE HELP ASAP !!!!!!!!!!!!!!!!!!!!!!!!!
disa [49]

Answer:

C. 15 votes

Step-by-step explanation:

B= votes Billy got

K = votes Keeton got

B = 3K


B+K =20

Substitute the first equation into the second equation

3K + K =20

Combine like terms

4K =20

Divide both sides by 4

4K/4 = 20/4

K =5

Keeton got 5 votes

B = 3*K

B = 3*5

B = 15 votes

Billy got 15 votes

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3 years ago
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ELEN [110]

Answer:

Since the base is the same, we can just multiply the exponents, and when we do so we get y^6.

7 0
2 years ago
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Determine the value of x which satisfies the following equation. <br> ln(4x+1)=6
Anika [276]

Answer:

Not Determinable

Step-by-step explanation:

Simplifying

Ln(4x + 1) = 6

Reorder the terms:

nL(1 + 4x) = 6

(1 * nL + 4x * nL) = 6

(1nL + 4nxL) = 6

Solving

1nL + 4nxL = 6

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Reorder the terms:

-6 + 1nL + 4nxL = 6 + -6

Combine like terms: 6 + -6 = 0

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The solution to this equation could not be determined.

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The line of reflection will (always, sometimes, never) be the perpendicular bisector between a preimage and it’s reflected image
frez [133]

Answer:

Step-by-step explanation:

line of reflection: <em>a fixed line directly in the middle of the pre-image and the reflected image. </em>

perpendicular: <em>two lines meeting at a 90 degree angle</em>

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pre-image: <em>the original figure before any transformation or translation has been made</em>

reflected image: <em>the original image after being reflected across the line of reflection.</em>

<em />

Is the line of reflection a line running perpendicular, directly in the middle of the pre-image and the reflected image? Yes, always would be my answer.

6 0
3 years ago
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