Answer:
Where is graph Hope you understand me
Answer:
y = -1/2x+2
Step-by-step explanation:
Two points on the line are (0,2) and (4,0)
We can find the slope
m = (y2-y1)/(x2-x1)
= (0-2)/(4 -0)
= -2/4
- 1/2
We know the y intercept is 2 since it crosses the y axis at 2
The slope intercept form is
y = mx+b where m is the slope and b is the y intercept
y = -1/2x+2
Answer:
![\Huge\boxed{A.8}](https://tex.z-dn.net/?f=%5CHuge%5Cboxed%7BA.8%7D)
Step-by-step explanation:
Hello There!
If you didn't know vertical angles are congruent
That being said we can use this equation to solve for x
40 = 5x
Objective: Isolate the variable using inverse operations
To get rid of the 5 we divide each side by 5
40 / 5= 8
5x/5=x
we're left with x=8
To check our answer we can plug in 8 to x and if it equal 40 then the answer is correct
5(8) = 40
So the answer would be 8
This kind of exercise can be real drudgery. But it's almost all simple arithmetic, so better you than me. I'll do one of these for you, which will show you how to do the other one.
a). sin · cot / sec
You're supposed to know that [ cotangent = cosine/sine ]
and [ secant = 1/cosine ].
Then the problem becomes
sin · (cos/sin) / (1/cos) = cos²
Aw shucks, I might as well also set up 'b)' for you:
b). cos · csc / tan
You're supposed to know that [ cosecant = 1/sine ]
and [ tangent = sine/cosine ].
Then the problem becomes
cos · (1/sin) / (sin/cos) = (cos/sin)²
Now simply plug in the given values of cos A and sin A .
And may I compliment you on your nail care !
Answer:
b. 239
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
![\alpha = \frac{1-0.99}{2} = 0.005](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B1-0.99%7D%7B2%7D%20%3D%200.005)
Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so ![z = 2.575](https://tex.z-dn.net/?f=z%20%3D%202.575)
Now, find M as such
![M = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which
is the standard deviation of the population and n is the size of the sample.
In this problem, we have that:
![M = 0.5, \sigma = 3](https://tex.z-dn.net/?f=M%20%3D%200.5%2C%20%5Csigma%20%3D%203)
![M = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
![0.5 = 2.575*\frac{3}{\sqrt{n}}](https://tex.z-dn.net/?f=0.5%20%3D%202.575%2A%5Cfrac%7B3%7D%7B%5Csqrt%7Bn%7D%7D)
![0.5\sqrt{n} = 7.725](https://tex.z-dn.net/?f=0.5%5Csqrt%7Bn%7D%20%3D%207.725)
![\sqrt{n} = 15.45](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%2015.45)
![n = 238.7](https://tex.z-dn.net/?f=n%20%3D%20238.7)
So a sample of at least 239 is required.
The correct answer is:
b. 239