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xxTIMURxx [149]
2 years ago
9

Only 3/5 of the University students wanted to become math teachers if 3500 did not want to become math teachers how many univers

ity students were there?”
Mathematics
1 answer:
Tasya [4]2 years ago
3 0

Answer:

8750

Explanation:

There are 5/5 math teachers in the university. 3/5 of them did not want to become math teachers which means 2/5 of the math teachers is equal to 3500.

3500=2/5

divide 3500 by 2 to get 1/5 of the math teachers.

3550/2=1750

1750 is 1/5 of the math teachers.

multiply 1750 by 5 to get 5/5 of the math teachers

1750*5= 8750

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What is the distance from (-4, -7) to (4, 8) ?
Mila [183]

Answer:

17

Step-by-step explanation:

We can use this formula:

\sqrt{(x2-x1)^2 + (y2 -y1)^2} where x and y indicate the coordinates of the two points

\sqrt{4-(-4)^2 + (8-(-7)^2} = \sqrt{64 + 225} = \sqrt{289} = 17

4 0
2 years ago
Read 2 more answers
There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=
yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = \frac{12P4}{12^{4} }

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = \frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }

P(X=2) = 0.401

P(X=3) = \frac{4C3 * 12P2}{12^{4} }

P(x=3) = 0.025

P(X=4) = \frac{12}{12^{4} }

P(X=4) = 0.001

Mean, \mu = \sum xP(x)

\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879

Standard deviation, SD = \sqrt{\sum x^{2} P(x) - \mu^{2}}  \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2}  * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}

SD = 1.033

4 0
3 years ago
High grade steel consists of 85% iron and 15% magnese. Low grade steel consists of 67% iron and 33% mag ese. NASA orders 500 ton
Mamont248 [21]

Answer:

361\dfrac{1}{9} tons of high steel and 138\dfrac{8}{9} tons of low steel

Step-by-step explanation:

Let x be the number of tons of high grade steel and y be the number of tons ow low grade steel needed.

In x tons of high grade steel there are

0.85x tons of iron

0.15x tons of magnese

In y tons of low grade steel there are

0.67y tons of iron

0.33y tons of magnese

NASA orders 500 tons of steel, so

x+y=500

and specifies that it must be in the proportion 80% iron and 20% magnese, so

0.85x+0.67y=500\cdot 0.8\\ \\0.85x+0.67y=400

From the first equation,

x=500-y

Substitute it into the second equation:

0.85(500-y)+0.67y=400\\ \\425-0.85y+0.67y=400\\ \\-0.18y=-25\\ \\y=\dfrac{2,500}{18}=138\dfrac{8}{9}\ tons\\ \\x=361\dfrac{1}{9}\ tons

7 0
3 years ago
Find the value for x​
d1i1m1o1n [39]

Answer:

Value of x --> 15°

<u>Step-by-step explanation:</u>

(2x + 60°) and 6x lie on a straight line. So, they form a linear pair. Their sum gives 180°.

---> (2x + 60°) + 6x = 180°

     2x + 60° + 6x = 180°

     8x + 60° = 180°

     8x = 180°- 60°

     8x = 120

      x = \frac{120}{8}

<h3><u>x equals 15°</u></h3>
5 0
2 years ago
Write a linear function f with the values f (-1) = 5 and f (3) = 4.<br> A function is f(x) =
Drupady [299]

Answer:

Step-by-step explanation:

Since we have points (-1,5) and (3,4) we can find the slope m of y=mx+b

m=(y2-y1)/(x2-d1)=(5-4)/(-1-3)=1/-4=-1/4 so we have

y=-x/4+b, using point (3,4) we can solve for the y intercept, b.

4=-3/4+b, b=19/4, so the line is

y=(-x+19)/4

5 0
2 years ago
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