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amid [387]
2 years ago
10

Please help me soon as possible !!!!!!!!!!

Mathematics
1 answer:
Oduvanchick [21]2 years ago
8 0
17) y-5=-3(x+2)
y=-3x-1
-3x-1
-3x=1
x=-1/3


18)y+1=4/5(x-5)
y=4x/5-5
4x/5-5=0
4x x5/5-5x5=0x5
4x-5x5=0x5
4x-25=0
4x=25
x=25/4


19)0=x-4
x-4=0
x=4

20)y-3=-1/2(x+4)
y=-x/2+1
-x/2+1=0
x=2

21)y-4=1/3(x+3)
y=x/3+5
x/3+5=0
x/3=-5
x=-5x3
x= -15

22) y+5=3(x+3)
y=3x+4
3x+4=0
3x=-4
x=-4/3

23) y-3=-2(x+2)
y=-2x-1
-2x-1=0
-2x=1
x=-1/2


24)y-1=5/3(x-3)
y=5x/3-4
5x/3-4=0
x=4x3/5
x=12/5
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Answer:

cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = -\frac{1}{3}

cos(b) = -\frac{1}{4}

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = -\sqrt{1-(-\frac{1}{3})^2} [Since, sin(a) = \sqrt{(1-\text{cos}^2a)}]

         = -\sqrt{\frac{8}{9}}

         = -\frac{2\sqrt{2}}{3}

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

sin(b) = -\sqrt{1-(-\frac{1}{4})^2}

         = -\sqrt{\frac{15}{16}}

         = -\frac{\sqrt{15}}{4}

By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

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3 years ago
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9x+9y=9. Solve for Y
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y = 1 - x

Step-by-step explanation:

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5 0
2 years ago
Read 2 more answers
If two supplementary angles are in the ratio of 4:5 the measure of the larger angle is
dimulka [17.4K]

Answer:

Step-by-step explanation:

Let the angles be 4x , 5x

4x + 5x = 180   { supplementary}

      9x = 180

        x = 180/9

        x = 20

Larger angle= 5x = 5* 20 = 100

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