Jerry takes 0.75 hours or
hours more to clean house than thomas
<h3><u>Solution:</u></h3>
Given that Jerry and Thomas own a cleaning business
Thomas cleans a house in
hours and Jerry cleans a house in
hours
To find: Number of hours more Jerry takes to clean than thomas
<em>Number of hours more Jerry takes to clean than thomas = time taken by Jerry - time taken by thomas</em>
Time taken by Jerry = ![3\frac{1}{4} = \frac{3 \times 4 + 1}{4} = \frac{13}{4} \text{hours}](https://tex.z-dn.net/?f=3%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cfrac%7B3%20%5Ctimes%204%20%2B%201%7D%7B4%7D%20%3D%20%5Cfrac%7B13%7D%7B4%7D%20%5Ctext%7Bhours%7D)
Time taken by Thomas = ![2\frac{1}{2} = \frac{2 \times 2 + 1}{2} = \frac{5}{2} \text{hours}](https://tex.z-dn.net/?f=2%5Cfrac%7B1%7D%7B2%7D%20%3D%20%5Cfrac%7B2%20%5Ctimes%202%20%2B%201%7D%7B2%7D%20%3D%20%5Cfrac%7B5%7D%7B2%7D%20%5Ctext%7Bhours%7D)
Substituting the values in above formula,
Number of hours more Jerry takes to clean than thomas = ![\frac{13}{4} - \frac{5}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B4%7D%20-%20%5Cfrac%7B5%7D%7B2%7D)
On solving we get,
![=\frac{13}{4} - \frac{5}{2}\\\\= \frac{26-20}{8}\\\\= \frac{6}{8} = 0.75](https://tex.z-dn.net/?f=%3D%5Cfrac%7B13%7D%7B4%7D%20-%20%5Cfrac%7B5%7D%7B2%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B26-20%7D%7B8%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B6%7D%7B8%7D%20%3D%200.75)
Thus Jerry takes 0.75 hours or
hours more to clean house than thomas