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2 years ago

I want a way to solve this question

Mathematics

1 answer:

leonid [27]2 years ago

6 0

Answer:

log xy3 the perimeter of the length in it multiply it 3 times you will get the answer. and try multiplying 6.1cm to 5kg

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The radius of the circle is 7 cm. What is the area of the circle in cm2? Leave answer in terms of pi

mash [69]

Answer:

49Pi cm^2

Step-by-step explanation:

Area of a circle = Pi r^2

Radius r = 7

Area = Pi x 7^2

= Pi x 7 x 7

= 49Pi cm^2

7 0

2 years ago

Please Help me! ASAP

kow [346]

Your answer would be 44

5 0

3 years ago

What size pizza should she order to get 37.68in of crust?

Alex17521 [72]

$\huge\fcolorbox{blue}{aqua}{Answer:}$

════════════════════

Answer:

↝ $r = \frac{471}{25\pi}$

Solution:

$2\pi r = 37.68$

$\frac{2\pi r}{2\pi} = \frac{37.68}{2\pi}$

$r = \frac{37.68}{2\pi}$

$r = \frac{471}{25\pi}$

────────────────────

If u evaluate it it will become

=5.996958256

════════════════════

Explanation:

#Carry on learning

7 0

1 year ago

Read 2 more answers

Express 0.0057 in scientific notation

andrew-mc [135]

Answer:

$5.7 \times {10}^{ - 3}$

Step-by-step explanation:

0.0057

first number

then the rest

equal

5.7

There's three zeros behind the number 5 which mean it will be -3

$\times {10}^{ - 3}$

final answer

$5.7 \times {10}^{ - 3}$

another example and it will be clear

0.0000403

first number

then the rest

equal

4.03

There's five zeros behind the number 4 which mean it will be -5

$\times {10}^{ - 5}$

final answer

$4.03 \times {10}^{ - 5}$

3 0

3 years ago

The layer of gold coating on a ring should be 0.03 millimeters thick when the ring is completed. A coating of 0.021 millimeters

Arisa [49]

The amount of gold coating in millimeters needed for the ring is the difference between the total coating and the coating that has already been applied. From the given above, that would be,
0.03 mm - 0.021 mm = 0.009 mm
Thus, the answer to this question is letter B.

6 0

3 years ago

Read 2 more answers

I want a way to solve this question​

I want a way to solve this question