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Akimi4 [234]
2 years ago
14

If TRAPis an isosceles trapezoid, what is the value of x?

Mathematics
1 answer:
mina [271]2 years ago
7 0

Answer:

C ..................................

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What is m∠ BAC???????
Korvikt [17]

Answer:

36 degrees

Step-by-step explanation:

I’m pretty sure that’s it

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3 years ago
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I don’t understand this I need help please
scoray [572]
The answer is B 2+(-35)
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Given (64y^2)+(4x^2)+128y+16x+64=0, transform the equation into the appropriate form
____ [38]

Answer:

(8y+8)²+(4x²+16)=0

Step-by-step explanation:

Given:

(64y²)+(4x²)+128y+16x+64=0

Find:

Equation into the appropriate form

Computation:

(64y²)+(4x²)+128y+16x+64=0

(8y)²+(2x)²+128y+16x+64=0

(8y)²+(2x)²+2(8y)(8)+2(2x)(4) + 8²=0

(8y+8)²+(4x²+16)=0

6 0
3 years ago
Please help me with this question!!
stepladder [879]

Answer:

  1. rational
  2. irrational
  3. irrational
  4. irrational
  5. √7, it is irrational

Step-by-step explanation:

A <em>rational</em> number is one that can be expressed as the ratio of two integers. All fractions that have integer numerators and (non-zero) denominators are <em>rational</em> numbers. Any finite decimal number, or any repeating decimal number, is a rational number. These can always be expressed as the ratio of two integers. For example, 0.4040... = 40/99, and 0.286 = 286/1000.

To make an irrational sum, at least one of the contributors must be irrational. You want an irrational 2-number sum that has 7/8 as one of the contributors. Since 7/8 is rational, the other contributor must be irrational.

__

<u>Step 1</u>. The number 7/8 is <em>rational</em>.

<u>Step 2</u>. The desired sum is <em>irrational</em>.

<u>Step 3</u>. The rule <em>rational + </em><em>irrational</em><em> = irrational</em> applies.

<u>Step 4</u>. An <em>irrational</em> number must be chosen.

Step 5. √7 will produce an irrational sum, because <em>it is irrational</em>.

5 0
2 years ago
Answer again plsss sorry thanks if you helped
cestrela7 [59]

Answer:

20% and 95%

Step-by-step explanation:

I know this is correct trust me!

7 0
3 years ago
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