Hey there
__________
The correct answer is
Whatever each CD costs, what each person paid is that cost times the number of CDs purchased (no sales tax for this problem).
So, the price of one CD is a factor of $66 (a number of $ that divides $66 evenly).
In theory, it could be $1, $2, $3, $6, $11, $22, $66.
It could even be $0.50, $0.25, $0.20, $0.10, $0.05,...
Also, the price of one CD must be a factor of $54. such as $54,$27,$18,$9,$6,$3,$2,$1,... .
You are looking for the most that price could be.
The grew greatest price that is in both lists is $6.
How can you make those lists?
You can start with the total price, then the price divided by 2, by 3, by whatever whole number you can divide it.
Otherwise, you could find the greatest common factor of 66 and 54
from the prime factorization of both numbers.
___________________
Hope this helps you
Answer:
x<(3b-5)/a
Step-by-step explanation:
Subtract 3b from both sides: -ax>5-3b
Divide by -a, when dividing/multiplying a negative you flip the </> sign: x<(3b-5)/a
Answer:
x=2
y=3
Step-by-step explanation:
y=−2x+7
y=5x−7
Set the two equations equal since they are both equal to y
−2x+7
=5x−7
Add 2x to each side
-2x+7+2x = 5x-7+2x
7 = 7x-7
Add 7 to each side
7+7 = 7x-7+7
14 =7x
Divide by 7
14/7 = 7x/7
2 =x
Now find 7
y = 5x-7
y = 5(2) -7
y = 10-7
y = 3
