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lawyer [7]
2 years ago
13

What does mean mean on sports teams

Mathematics
1 answer:
STALIN [3.7K]2 years ago
4 0

Answer:

Physical activy used for pleasure.

Step-by-step explanation:

It's just a meaning so I can't provide an explanation.

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A football is 64 metres wide and 118 metres long. what is its perimeter?
ratelena [41]
I guess you're asking the football court?? cuz a football is sphere shape.
for a rectangular shape just add the width and length together then mmultiply it by 2.
so
(64+118)x2
= 364 m2
7 0
3 years ago
Please help!!<br> I don’t know what to do
ira [324]

Answer:

x = 14.4

Step-by-step explanation:

Similar means that the figures are proportional to each other. Because of this, we can form a problem. \frac{9}{5} (the short side lengths) = \frac{x}{8} (the long side lengths). Now we can solve this by cross-multiplying. If we multiply 9 · 8 we get 72, and 5 · x is 5x. 72 = 5x. Now divide both sides by 5. 72 ÷ 5 = 14.4. Therefore, x should be equal to 14.4. Does this make sense?

6 0
3 years ago
Connor scored 14,370 points in a game amy scored 1,089 fewer points than conor . how many points did amy score
Mice21 [21]
Amy scored 13,281 points. 
7 0
3 years ago
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If a backpack can fit 10 pounds of good, how many backpacks are necessary for 35 pounds of good.
slega [8]

Answer:

3.5

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5 0
3 years ago
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Listed below are amounts​ (in millions of​ dollars) collected from parking meters by a security service company and other compan
Vikentia [17]

Answer:

CV=\frac{0.1252}{1.57}=0.07975

CV=\frac{0.1317}{1.72}=0.07657

The relative variability is almost equal in both samples a slight greater variability can be noticed in the first sample.

Step-by-step explanation:

The coefficient of variation of a sample is defined as the ratio between the mean standard deviation and the sample mean. And it represents the percentage relation of the variation of the data with respect to the average.

CV=\frac{S}{\bar X}

In the case of the first sample you have:

CV=\frac{0.1252}{1.57}=0.07975

In the case of the second sample you have:

CV=\frac{0.1317}{1.72}=0.07657

The relative variability is almost equal in both samples a slight greater variability can be noticed in the first sample.

6 0
3 years ago
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