This is the concept of geometry, given that AB=AC, it means that the tirangle is isosceles, thus to get the value of AB and AC we proceed as follows;
thus using the cosine rule:
c^2=a^2+b^2-2abcosC
suppose\AB=AC=x
thus;
8^2=x^2+x^2-2*x*xcos15
64=2x^2-2x^2cos15
64=2x^2-1.9x^2
64=0.1x^2
x^2=640
x=sqrt640
x=25.3
hence;
AC=AB=25.3
Answer:
3(2) x 11 = 99
2(2) x 3(2) = 36
3(2) x 5 = 45
5(1) = 5
2(3) x 3 = 24
Step-by-step explanation:
I hope this helps you out!
10 / .2 = 50. Answer = 50
<span>x^2-2x-3=0
(x-3)(x+1)=0 [factor]
x-3=0 [set each factor equal to zero and solve for the x-value]
x=3
and
x+1=0
x=-1
So, the solutions are x = 3 and x = -1</span>