Question

Unit 3 - Task 3 - (10 points)

Answer 1

The 50th term in the sequence is 199

Arithmetic sequence

The nth term of an arithmetic sequence is expressed as:

Tn = a+ (n - 1)d

where:

• a is the first term
• n is the number of terms
• d is the common difference

The sequence formed by the amount of Whatchamacallits produced as;

3, 7, 11, 15...

a = 3

d = 11-7 = 7-3 = 4

Substitute

Tn = 3 + (n-1) * 4
Tn = 3 + 4n -4

Tn = 4n - 1

Hence the explicit formula that models the production for the nth term of the sequence is Tn = 4n - 1

If n = 50

T50 = 4(50) - 1

T50 = 199

Hence the 50th term in the sequence is 199

Learn more on sequence here; brainly.com/question/6561461