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VashaNatasha [74]
2 years ago
14

In order for cos 53° = sin A, what must be the measure of _A? = 53° 37° 127° 90°

Mathematics
1 answer:
Ray Of Light [21]2 years ago
3 0

Answer:

the answer is 37..............

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Find all solutions of each equation on the interval 0 ≤ x<2π.
Aleksandr [31]

Answer:

x = 0 \: or \:x =   \pi

Step-by-step explanation:

The given equation is

\tan^{2} (x) \sec^{2} (x)  + \sec^{2} (x)  - \tan^{2} (x) =  2

Subtract 2 from both sides and factor by grouping to get:

\sec^{2} (x)(\tan^{2} (x) + 2)  -1( \tan^{2} (x)  +  2)

(\tan^{2} (x) + 2) (\sec^{2} (x) - 1) = 0

By the zero product principle:

(\tan^{2} (x) + 2) = 0 \: or \:  (\sec^{2} (x) - 1) = 0

(\tan^{2} (x)  =  - 2 \: or \:  \sec^{2} (x)  =  1

When

\sec^{2} (x)  =  1 \implies\cos^{2} (x)  =  1

\implies \:  \cos(x)  =  \pm1

This implies

x = 0 \: or \:x =   \pi

When

{ \tan }^{2} (x) =  - 2

We have

\tan(x)  =  \pm \sqrt{ - 2}

hence x is not defined for all real numbers

6 0
3 years ago
Read 2 more answers
PLS ASAP!! Thank You
Lady bird [3.3K]

Answer:

y = \frac{1}{2}x - 4

Step-by-step explanation:

Given

y = \frac{1}{2}x

Required

Shift 3\ units down and 2\ units right

y = \frac{1}{2}x

<u>Shift 3 units down</u>

The rule is: (x,y)=> (x,y-a)

Where a is the number of units shifted down

In this case: a = 3

So, we have:

y = \frac{1}{2}x == > y = \frac{1}{2}x - 3

<u>Shift 2 units right</u>

The rule is: (x,y)=>(x-b,y)

Where b is the number of units shifted right

In this case: b = 2

So, we have:

y = \frac{1}{2}x - 3 ==> y = \frac{1}{2}(x - 2) - 3

Open bracket:

y = \frac{1}{2}x - 1 - 3

y = \frac{1}{2}x - 4

Hence, the new equation after the transformation is:

y = \frac{1}{2}x - 4

7 0
3 years ago
See picture^<br><br> i will give brainliest to the first person who answers
Masja [62]

Answer:

The two 50ml bottles

Step-by-step explanation:

(I will be using the $ but just change the sign to the euros)

$55/80ml= .68 per ml

45+22.5= $67.5

67.5/100 is about $.67

Therefor the two 50ml bottles is cheaper per ML and you get more product

8 0
3 years ago
Read 2 more answers
Through any three noncollinear points, there is exactly one plane containing them. Points W, X, and Y are noncollinear.
olga2289 [7]
Correct!

When thinking of what determines a plane we can make the following comparison.

If a plane was the top part of a table, 3 legs, whose tops are points W, X and Y may hold it, as shown in the first picture.

but if the legs are in a line, as in the second figure, they may not hold the top part, so 3 collinear points cannot determine a plane. 

5 0
3 years ago
Read 2 more answers
On Monday, the students in Mr. Carson’s class worked in pairs. On Tuesday, the students worked in groups of 3. On Wednesday, the
qwelly [4]
The smallest number of students in the class is the smallest number that is divisible by 2, 3, and 4. You need the least common multiple of 2, 3, and 4.
This is like finding the least common denominator.

Find the prime factors of the three numbers:
2 = 2
3 = 3
4 = 2^2

To find the LCM you need common factors, and not common factors with the larger exponent.

Now single factor is common to all numbers.
There is 2 and 2^2, so use 2^2 since it has the larger exponent.
There is also a 3, so use the 3.

LCM = 2^2 * 3 = 4 * 3 = 12

Mr. Carson's class may have 12 students. 12 is the smallest number of students it can have.

3 0
4 years ago
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