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2 years ago

6

8. The measure of ZH is (11x - 29). If x= 19,

1 answer:

frez [133]2 years ago

4 0

Answer:

given ,

$\bold{ZH = (11x - 29)}$

Also ,

$\bold{x = 19}$

substituting the value of x in the value of ZH , we get

$\bold{ZH = 11(19) - 29 }\\\bold{ ZH = 209 - 29 }\\ \bold\blue{ZH = 180}$

hope helpful~

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3 years ago

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Answer:

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Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

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$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

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$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

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$Term \to 2 * 3^n$ ---- n

So, the summation is:

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$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

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$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

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2 years ago

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TiliK225 [7]

Answer:

By making y alone

Step-by-step explanation:

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3 years ago