Answer:
a)The second student arrive 7 minutes and 36 seconds sooner
b)They have to walk 598,51 m
Step-by-step explanation:
Speed= Distance/Time
We are looking for time now
Time = Distance/Speed
First student
Time = 780 m/0.90 m/s=866,66 seconds
Second student
Time = 780 m/1.90 m/s=410,52 seconds
Difference=866,66-410,52= 456,14 seconds
In minutes
Difference= 456,14 seconds /60=7 minutes 36 seconds
Distance=Speed x Time
Speed¹ x Time¹ =Speed² x Time²
Time¹= Time² + 5.50 min
5.50 min =350 seconds
Time² =Speed¹ x Time¹ /Speed²
Time² =Speed¹ x (Time² + 350 seconds ) /Speed²
Time² =0.9 x (Time² + 350 seconds ) /1.9
Time² =0,4737 x (Time² + 350 seconds )
Time² =0,4737 Time² + 165,79 seconds
Time² - 0,4737 Time² = 165,79 seconds
0,5263 Time² = 165,79 seconds
Time² = 165,79 seconds/0,5263 =315,01 seconds
Distance=1,9 x 315,01 seconds = 598,51 m
