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faltersainse [42]

3 years ago

5

I feel like crying please help me

1 answer:

LekaFEV [45]3 years ago

8 0

Hey there!

To start, the slope intercept equation format is y=mx+b where m=the slope and b=the y-intercept.

Because you appear to have a coordinate set to plug in for x and y as well as a slope of 4, you can plug your known values into the slope intercept equation:
y=mx+b
coordinate: (1,6)
y=6 (the y value of the coordinate point)
x=1 (the x value of the coordinate point)
m=4 (the slope of the equation, given)

6=4(1)+b

Because b, your y-intercept is your only missing value, you can simplify your equation and solve for b:
6=4(1)+b
6=4+b
b=2

Now that you have your two needed values, your slope and your y-intercept, your final equation should be y=4x+2, or the third choice.

Hope this helps and I hope you have a wonderful rest of your day! :)

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An acre measures 4840 square yards. In a city a lot on which a single family house can be built measures 40 feet across and 100

maw [93]

We are required to find the percent of an acres is this lot

The percent of acres of the lot is 27.55%

Area of an acre = 4840 square yards

Area of the lot = Length × width

= 40 feet × 100 feet

= 4000 square feet

<em>convert feet to yards</em>

1 foot = 0.333333

4000 square feet = 1333.333 square yards

Therefore,

Area of the lot = 1333.333 square yards

percent of an acres is this lot = 1333.333 / 4840 × 100

= 0.2754820247933 × 100

= 27.548202479338

Approximately,

27.55%

Therefore,

The percent of acres of the lot is 27.55%

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The range of all real numbers x such that 2x − 5 < 7 and 4x + 10 > 6 is

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2x - 5 < 7
2x = 12
x = 6

4x + 10 > 6
4x = - 4
x = - 1

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If P(A)=0.3, then the probability of the complement of A is ?

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On Monday, Noah finds 19 big grasshoppers and 9 small ones in his garden. What is the experimental probability of finding a smal

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Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

3 years ago