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3 years ago

Plz help fast! worth 100 points

Mathematics

2 answers:

zloy xaker [14]3 years ago

6 0

An equilateral triangle sides are all equal to each other. This means that is one side of an equilateral triangle is x + 3 then the sides of the other two triangles as also each x + 3

The formula for perimeter of a triangle is:

Perimeter = side 1 + side 2 + side 3

Or in the case of an equilateral triangle it would be:

Perimeter = 3(side)

This means that for the formula of this equilateral triangle you have:

Perimeter = 3(x + 3)

If asked the three out side of the parentheses can be distributed, meaning that you multiply the outside number (in this case that is 3) to all the number inside the parentheses (in this case that is x and 3)

Perimeter = (3 * x) + (3*3)

Perimeter = 3x + 9

Both of these are correct:

P = 3(x + 3)

P = 3x + 9

Hope this helped!

~Just a girl in love with Shawn Mendes

katen-ka-za [31]3 years ago

6 0

Answer:

3x+9

Step-by-step explanation:

3(x+3)

3x+9

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3 years ago

10 – 7x = 2 - 8x help :)

Rudik [331]

10-7x=2-8x

We move all terms to the left:

10-7x-(2-8x)=0

We add all the numbers together, and all the variables

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3 years ago

Read 2 more answers

Evaluate the surface integral. s x ds, s is the part of the plane 18x + 9y + z = 18 that lies in the first octant.

IceJOKER [234]

In the first octant, the given plane forms a triangle with vertices corresponding to the plane's intercepts along each axis.

$(x,0,0)\implies 18x+9\cdot0+0=18\implies x=1$
$(0,y,0)\implies 18\cdot0+9y+0=18\implies y=2$
$(0,0,z)\implies 18\cdot0+9\cdot0+z=18\implies z=18$

Now that we know the vertices of the surface $\mathcal S$ , we can parameterize it by

$\mathbf s(u,v)=\langle(1-u)(1-v),2u(1-v),18v\rangle$

where $0\le u\le1$ and $0\le v\le1$ . The surface element is

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|\,\mathrm du\,\mathrm dv=2\sqrt{406}(1-v)\,\mathrm du\,\mathrm dv$

With respect to our parameterization, we have $x(u,v)=(1-u)(1-v)$ , so the surface integral is

$\displaystyle\iint_{\mathcal S}x\,\mathrm dS=2\sqrt{406}\int_{u=0}^{u=1}\int_{v=0}^{v=1}(1-u)(1-v)^2\,\mathrm dv\,\mathrm du=\frac{\sqrt{406}}3$

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3 years ago

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Jlenok [28]

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3 years ago

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miss Akunina [59]

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3 years ago

Plz help fast! worth 100 points ​

Plz help fast! worth 100 points