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hjlf
2 years ago
14

I need help with algebra​

Mathematics
1 answer:
Arlecino [84]2 years ago
3 0

Answer:

Hello, my name is 1frogaroni feel free to ask any questions about algebra such as equations you don't understand. I will try my best to help you out with your question :)

Step-by-step explanation:

Oh and welcome to brainly where the community will be glad to help you!

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(15 points please help)
dsp73
C. You can graph it on Desmos and all the given points work. 
5 0
3 years ago
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Whats the table for y=-4|x-5|+3 <br>how to solve absolute value function with a table and graph
zepelin [54]

Answer:

For a table for x and y values for this absolute value equation, it would look like this:

x --- y

3 --- (-5)

4 --- (-1)

5 --- 3

6 --- (-1)

7 --- (-5)

Step-by-step explanation:

When you are building a table for an absolute value graph, you start with the base formula for absolute value equations:

y = a|x-h| + k

In this equation (h, k) is the vertex and therefore the middle point. From there we go two numbers in each direction for our x values. And for every change in x, y changes by a factor of a.

3 0
3 years ago
You are thirsty,so a friend has offered to give you 50% of his water.What information must you have in order to find out how muc
goldfiish [28.3K]
You need to find out how much water he has left .c
6 0
3 years ago
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Find the solution set of this inequality. Select<br> the correct graph.<br> |-8x+4|&gt;12
scoundrel [369]

Answer:

The first option is correct

Step-by-step explanation:

Hope it is helpful....

3 0
3 years ago
A researcher wants to test if the mean annual salary of all lawyers in a city is different from $110,000. A random sample of 50
KiRa [710]

Solution :

This is the two tailed test.

The null hypothesis and the alternate hypothesis is as :

Null hypothesis is $H_0:\mu=110000$

Alternate hypothesis is $H_0:\mu \neq110000$

$\overline x = 112000, \ \mu = 110000, \sigma = 16100, n =  50, \alpha = 0.02$

Therefore, the critical value of z is :

$z_{\alpha} = -2.33 \text{ and}\  2.33$

Now the test statics is :

$z=\frac{\frac{(\overline x - \mu)}{\sigma}}{\sqrt n}$

$z=\frac{\frac{(112000-110000)}{16100}}{\sqrt {50}}$

$z=0.87$

The test statics is 0.878

We see that it is a right tailed test.

$P(z > 0.878)=1-P(z

$P- \text{value}= \ 2 \times 0.19$

              = 0.3800

Thus , P-value > α

So we fail to reject the null hypothesis.

5 0
2 years ago
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