Marie has bought a plant which she needs to transfer from its cylindrical pot to the ground. The pot has diameter 10 cm and is 2
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Break the shape into smaller rectangles and solve for there areas. Then add the areas together to get the total area of the figure. See the picture below where I solved the problem
If Chisaka does not space walks, the days she spend spacewalking are equal to zero. Since <span>S represents the number of days Chisaka spacewalks, we just need to replace </span>
in our inequality to find how long her food will last if she does not spacewalks:
From this calculation we can infer that the coefficient of N, 1.3, is the amount of food she needs per day if she doesn't spacewalks. Similarly the coefficient of S, 2.2, is the amount of food she need per day if she spacewalks.
We can conclude that Chisaka will need 1.3 kg of food if she doesn't spacewalks, and 2.2 kg of food if she spacewalks.
From this calculation we can infer that the coefficient of N, 1.3, is the amount of food she needs per day if she doesn't spacewalks. Similarly the coefficient of S, 2.2, is the amount of food she need per day if she spacewalks.
We can conclude that Chisaka will need 1.3 kg of food if she doesn't spacewalks, and 2.2 kg of food if she spacewalks.
The length of the rectangle is = 72 cm
The width of the rectangle is = 56 cm
Area of the rectangle is =
= cm²
As given, the other rectangle has the same area as this one, but its width is 21 cm.
Let the length here be = x
Hence, length is 192 cm.
We can see that as width decreases, the length increases if area is constant and when length decreases then width increases if area is constant.
So, in the new rectangle,constant of variation=k is given by,
or
Hence, the constant of variation is