PLEASE HELP!!!!!! The length of a rectangle is three times its width. If the perimeter of the rectangle is 56 cm, find its area.
1 answer:
Step-by-step explanation:
l = length
w = width
l = 3w
perimeter p = 2l + 2w = 56
using the identity of the first equation
p = 2(3w) + 2w = 56
6w + 2w = 56
8w = 56
w = 7 cm
l = 3w = 3×7 = 21 cm
so, the area is
l×w = 21×7 = 147 cm²
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