Answer:
yes the sides of a triangle can have all those sides
 
        
             
        
        
        
Answer:

Step-by-step explanation:
Simplify both of the fractions so  to get 0.93 and
 to get 0.93 and  to get 0.57.
 to get 0.57.
Then you put them back into fraction form.
 
        
             
        
        
        
We have:
Event A ⇒ P(A) = 0.16
Event B ⇒ P(B) = 0.09
Probability of event B given event A happening, P(B|A) = P(A∩B) / P(A) = 0.12
By the conditional probability, the probability of event A and event B happens together is given by:
P(B|A) = P(A∩B) ÷ P(A)
P(B|A) = P(A∩B) ÷ 0.16
0.12 = P(A∩B) ÷ 0.16
P(A∩B) = 0.12 × 0.16
P(A∩B) = 0.0192
When two events are independent, P(A) × P(B) = P(A∩B) so if P(A∩B) = 0.0192, then P(B) will be 0.0192 ÷ 0.16 = 0.12 (which take us back to P(B|A))
Since P(B|A) does not equal to P(B), event A and event B are not independent.
Answer: <span>Events A and B are not independent because P(B|A) ≠ P(B)</span>
        
             
        
        
        
Let x = adult tickets
Let y = children's tickets
x + y = 800
8x + 4y = 4,400
From the first eq, x = 800 - y, plug this in to the second eq
8(800-y) + 4y = 4,400
6400 - 8y + 4y = 4,400
2000 = 4y
500 = y
x = 800 - 500
x = 300
300 adult tickets were sold.