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2 years ago

Help with question pls I don't understand

Mathematics

2 answers:

Mazyrski [523]2 years ago

6 0

Answer:

15x^3y+6x^2y^2+9xy^3

Step-by-step explanation:

3xy ( 5x^2 +2xy +3y^2)

Distribute the 3xy to all terms in the parentheses

3xy*5x^2+3xy*2xy+3xy*3y^2

15x^3y+6x^2y^2+9xy^3

Verdich [7]2 years ago

5 0

Answer:

15 $x^{3}$ y + 6 $x^{2}$ $y^{2}$ + 9x $y^{3}$

Step-by-step explanation:

multiple everything in the brackets by 3xy

3xy x 5 $x^{2}$ = 15 $x^{3}$ y

3xy x 2xy = 6 $x^{2}$ $y^{2}$

3xy x 3 $y^{2}$ = 9x $y^{3}$

15 $x^{3}$ y + 6 $x^{2}$ $y^{2}$ + 9x $y^{3}$

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Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun

WITCHER [35]

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Required solution (a) $f(x,y,z)=xyz+3z^2+C$ (b) 40.

Step-by-step explanation:

Given,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k$

(a) Let,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}$

Then,

$f_x=yz,f_y=xz,f_z=xy+6z$

Integrating $f_x$ we get,

$f(x,y,z)=xyz+g(y,z)$

Differentiate this with respect to y we get,

$f_y=xz+g'(y,z)$

compairinfg with $f_y=xz$ of the given function we get,

$g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)$

Then,

$f(x,y,z)=xyz+h(z)$

Again differentiate with respect to z we get,

$f_z=xy+h'(z)=xy+6z$

on compairing we get,

$h'(z)=6z\implies h(z)=3z^2+C$ (By integrating h'(z)) where C is integration constant. Hence,

$f(x,y,z)=xyz+3z^2+C$

(b) Next, to find the itegration,

$\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40$

3 0

3 years ago

Help with question pls I don't understand​

Help with question pls I don't understand