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RSB [31]
2 years ago
7

1 1/4 x 3/4 as a fraction

Mathematics
2 answers:
Vilka [71]2 years ago
5 0

Answer:

2 and 1/16th! ^^

Step-by-step explanation:

nlexa [21]2 years ago
5 0

Answer:15/16

Step-by-step explanation:

1 1/4×3?4

= 5/4×3/4

= 5 × 3/4 × 4

= 15/16

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PLEASE CAN SOMEONE EXPLAIN THIS TO ME . I DONT KNOW HOW TO DO IT
Gekata [30.6K]

Answer:

35

Step-by-step explanation:

-5{3-2[1-4(3-2^2)]}

we work inside out

using PEMDAS

parenthesis, exponents, multiply and divide, add and subtract

the very most inside

(3-2^2)

do the exponents

3 - 4 = -1

replace where it was in the original equation

-5{3-2[1-4(-1)]}

take the next set of parenthesis (bracket are the same as parenthesis)

[1-4(-1)]

multiply

4*-1 = -4

1--4 = 1+4 = 5

replace  where it was in the original equation

-5{3-2[5]}

next set of parenthesis

{3-2[5]}

3 - 10 = -7

replace  where it was in the original equation

-5 {-7}

35

3 0
3 years ago
होत है।<br>(2) सभी सर्वांगसम बहुभुज<br>भी होते हैं<br>​
Kobotan [32]
367 it’s also equivalent to 338
6 0
3 years ago
An elevator travels 310 ft in 10 seconds at that speed how far can this elevator travel in 12 seconds explain your reasoning
marta [7]

Answer:

<u>372 ft</u>

Step-by-step explanation:

This can be solved through cross multiplication.

310ft/10sec= x/12sec

Multiply the values across from each other. (A good way to know you've done it properly is if the numbers you multiplied are in different measurements. ex: 1 value is feet,  the other is seconds)

310 x 12 = 3720

Divide by the remaining value.

3720 / 10 = 372

8 0
3 years ago
You are given a cube with a length of 2.5 cm a width of 2.5 cm and a heigh of 2.5 cm and its mass is 295 g what is the density
Klio2033 [76]
Density = mass/volume
Volume = length x width x height
Volume = 2.5 x 2.5 x 2.5 
             = 15.625 cm^3
Density = 295/15.625
             = 18.88 g/cm^3
4 0
4 years ago
What is the ratio of the perimeter of ΔHKO to the perimeter of ΔFGO
Lera25 [3.4K]

Answer:

Part 1) The ratio of the perimeter of ΔHKO to the perimeter of ΔFGO is \frac{1}{2}

Part 2) The ratio of the area of ΔKHO to the area of ΔGFO is \frac{1}{4}

Step-by-step explanation:

Part 1)

we know that

If two figures are similar , then the ratio of its perimeters is equal to the scale factor

In this problem

Triangles HKO and FGO are similar by AAA Theorem

Find the scale factor

The scale factor is equal to the ratio of its corresponding sides

\frac{4}{8}=\frac{7}{14}=\frac{1}{2}

Part 2) Find the ratio of the area of ΔKHO to the area of ΔGFO

Area of ΔKHO

A=4*7/2=14\ units^{2}

Area of ΔGFO

A=8*14/2=56\ units^{2}

The ratio of its areas is equal to

\frac{14}{56}=\frac{1}{4}

Alternative Method

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

In this problem we have that

The scale factor is \frac{1}{2}

so

squared the scale factor

(\frac{1}{2})^{2}=\frac{1}{4} ----> is correct

7 0
3 years ago
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