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2 years ago

Please help with this question!

Mathematics

1 answer:

den301095 [7]2 years ago

6 0

I can not see the last option but I think it’s A

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If janice plays a game once and the probability of getting yellow is 0.24. How many times will the color shown be yellow if she

blsea [12.9K]

Answer: 12

Step-by-step explanation:

Given

The probability of getting yellow color is 0.24

If the no of trials is 50

$\text{No. of times yellow color shown(N) is}=p\times \text{no of trails}\\\Rightarrow N=0.24\times 50=12\ \text{times}$

Yellow color appears 12 times

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2 years ago

2x - y when x = 0 and y = -5

nata0808 [166]

Answer:

Step-by-step explanation:

2x - y when x = 0 and y = -5

2(0) - (-5) =

= 0 + 5

= 5

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2 years ago

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Twelve less than a p <br> number is two

Ipatiy [6.2K]

Answer:

P = 14

Step-by-step explanation:

First of all we know that P - 12 = 2

So, basically all we have to do is add 12 plus 2.

12 + 2 = P

P = 14

So, P should equal 14.

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2 years ago

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Find the slope and Y-intercept for each table, and then write an equation.

Leni [432]

Answer:

a. Slope = 2; y-intercept = 2

b. Slope = 2; y-intercept = 3

c. Slope = 2; y-intercept = -1

d. Slope = -2; y-intercept = 5

e. Slope = -3; y-intercept = -5

d. Slope = -2; y-intercept = 1

Step-by-step explanation:

I Hope That This Helps! :)

8 0

2 years ago

Help thankss <br>answer is <br><img src="https://tex.z-dn.net/?f=%20%28%20-%2014.0%29" id="TexFormula1" title=" ( - 14.0)" alt="

lyudmila [28]

We have point $P=(x_0,y_0)=(2,-4)$ , so first calculate $f'(x_0)$ . There will be:

$y=f(x)=2x^3-5x^2\\\\\\\\f'(x)=\big(2x^3-5x^2\big)'=\big(2x^3\big)'-\big(5x^2\big)'=2\big(x^3\big)'-5\big(x^2\big)'=\\\\=2\cdot3x^2-5\cdot2x=\boxed{6x^2-10x}\\\\\\\\f'(x_0)=f'(2)=6\cdot2^2-10\cdot2=6\cdot4-20=24-20=\boxed{4}$

Now, we can write the equation of the normal line as:

$y-y_0=-\dfrac{1}{f'(x_0)}(x-x_0)\\\\\\ y-(-4)=-\dfrac{1}{4}(x-2)\\\\\\y+4=-\dfrac{1}{4}x+\dfrac{1}{2}\\\\\\y=-\dfrac{1}{4}x+\dfrac{1}{2}-4\\\\\\\boxed{y=-\dfrac{1}{4}x-\dfrac{7}{2}}$

Normal line (and every line) crosses x-axis when y = 0, so coordinates of A:

$\boxed{y=0}\qquad\qquad\text{and}\\\\\\y=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\
0=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\\dfrac{1}{4}x=-\dfrac{7}{2}\quad|\cdot4\\\\\\x=-\dfrac{7\cdot4}{2}\\\\\\x=-7\cdot2\\\\\\\boxed{x=-14}\\\\\\\boxed{A=(-14,0)}$

8 0

2 years ago