The
lateral area of a cone is the surface area (aka area of the sides of the object) minus the area of the base of the cone.
The equation for the lateral area of a cone is:
where r = radius and l = slant height.
Since you know that the lateral area =
and the radius, r = 50 cm, you can plug those values into the equation for the lateral area and solve for l, the slant height:
The slant height of the cone is A) 10cm.
Step-by-step explanation:
or,(x-2)(x-4)+(3x-11)(x-3)/(x-3)(x-4)=(4x+13)/(x+1)
or,x^2-4x-2x+8+3x^2-9x-11x+33/x^2-4x-3x+12=(4x+13)/(x+1)
or,4x^2-4x-2x-9x-11x+8+33/x^2-7x+12=(4x+13)/(x+1)
or,4x^2-26x+41/x^2-7x+12=(4x+13)/(x+1)
or, (x+1)(4x^2-26x+41)=(4x+13)(x^2-7x+12)
or,4x^3-26x^2+41x+4x^2-26x+41=4x^3-28x^2+48x+13x^2-91x+156
or,-26x^2+4x^2+28x^2-13x^2+41x-26x-48x+91x=156-41
or,-7x^2+58x=115
or,-7x^2+58x-115=0
or,-(7x^2-58x+115)=0
or,7x^2-58x+115=0
or,7x^2-(35+23)x+115=0
or,7x^2-35x-23x+115=0
or,7x (x-5)-23 (x-5)=0
or, (x-5)(7x-23)=0
Either, Or,
(x-5)=0 (7x-23)=0
or,x=0+5 or,7x=23
:x=5 :x=23/7
Hence,x=5 or 23/7
I just learned about it. Simple!
6x=5x+7
Subtract 5x from both sides.
-5x -5x
You end up with
1x=7 or x=7
9/4 = 2 1/4
1/4 = 0.25
2.25 is your answer
hope this helps
Let's see
In ∆ABE and ∆CBE
- BE=BE(Common side)
- AE=EC[Diagonals of a parallelogram bisect each other]
- <AEB=<BEC[90°]
So by
SAS congruence the triangles are congruent
AB=BC
Fact:-
It's already given AC is perpendicular to BD
- It means diagonals are perpendicular to each other
According to general property of rhombus this parallelogram is also a rhombus.
So sides are equal hence AB =BC
