The expression 4x^2 represents - (4)(x)(x)
Given
R is the interior of ∠ TUV.
m∠ RUV=30degrees, m∠ TUV=3x+16, and m∠ TUR=x+10.
Find the value of x and the m ∠TUV.
To proof
As given in the question
m ∠TUV=3x+16, and m ∠TUR=x+10
thus
m∠ RUV = m∠ TUV - m∠ TUR
= 3x + 16 - x -10
= 2x + 6
As given
m ∠RUV=30°
compare both the values
we get
30 = 2x + 6
24 = 2x
12 = x
put this value in the m ∠TUV= 3x+16
m ∠TUV= 12× 3 +16
= 52°
Hence proved
Answer:
1 . given
2. given
3. transitive properties of congruence ...
4 .AAS
It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:
5.3
Step-by-step explanation:
(x − 6)(x + 0.7) = 0
using the zero product property
x-6=0 x+.7 =0
x-6+6 = 0+6 x+.7 -.7 = 0-.7
x = 6 x= -.7
sum of the solutions
6+-.7 = 5.3
