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Pavel [41]
3 years ago
10

Devon wants to write an equation for a line that passes through 2 of the data points he has collected. The points are (8, 5) and

(–12, –9). He writes the equation. 7x – 10y = 3. Is this a good model? Explain your reasoning.
Mathematics
2 answers:
melamori03 [73]3 years ago
6 0
Use slope formula to find slope <span><span><span>−9−5</span><span>−/12−8</span></span>=<span><span>−14/</span><span>−20</span></span>=<span>7/10</span></span> 7/10 = m = slope  
y= mx + b
y= (7/10)x + b
(8,5)
(5) = (7/10)(8) + b
b = -3/5

So.... <span>y=(<span>7/10)</span>x −<span>35

</span></span> multiply by 10

<span>10y=7x−6</span><span> --> -7x + 10y = -6
 --> 7x - 10y = 6
 So, if 7x - 10y = 3 a good model?</span>
miskamm [114]3 years ago
6 0

Answer:

If the model is good, then both points will check in the equation. Substituting 8 for x and 5 for y in the equation results in 56 – 50 = 3, which is not true. Therefore, the model is not good. Using (–12, –9) as a check results in –84 + 90 = 3. The constant value in the equation should be 6, not 3. In slope-intercept form, the y-intercept should be –3/5. Hope this helps!!! :)

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Tatiana [17]

Answer:

15 square units.

Step-by-step explanation:

To find the area, we must find the width and length of the rectangle. To find the width and length, we need to find the length of AB and the length of BC. We use the distance formula.

AB: A(-8, 3); B(-3, 3).

\sqrt{(-8-(-3))^2+(3-3)^2}

= \sqrt{(-8+3)^2+0^2}

= \sqrt{(-5)^2+0}

= \sqrt{25 }

= 5

BC: B(-3, 3); C(-3, 6).

\sqrt{(-3-(-3))^2+(3-6)^2}

= \sqrt{(-3 + 3)^2+(-3)^2}

= \sqrt{(0)^2+9}

= \sqrt{0+9}

= \sqrt{9}

= 3

Now that we have both the width and the length, we can solve for the area using A = lw, where A is the area, l is the length, and w is the width. In this case, l = 5 and w = 3.

A = lw

A = 5 * 3

A = 15

So, the area of the rectangle is 15 square units.

Hope this helps!

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3 years ago
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