the standard form of a quadratic formula is
y = ax^2 + bx + c
in this case you will solve using foil method
(× - 4)(x + 3)
<em>(</em><em>x</em><em> </em><em>×</em><em> </em><em>x</em><em>)</em><em> </em><em>+</em><em>(</em><em> </em><em>x</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>)</em><em>(</em><em>-</em><em> </em><em>4</em><em> </em><em>×</em><em> </em><em>x</em><em>)</em><em> </em><em>(</em><em> </em><em>-4</em><em>)</em><em>×</em><em> </em><em>3</em><em>)</em><em>)</em>
<em>x</em><em>^</em><em>2</em><em> </em><em>+</em><em> </em><em>3x</em><em> </em><em>-</em><em> </em><em>4x</em><em> </em><em>-12</em>
<em>x</em><em>^</em><em>2</em><em> </em><em>-</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>1</em><em>2</em>
<em>therefore</em><em> </em>
<em>y</em><em> </em><em>=</em><em> </em><em>x^</em><em>2-</em><em> </em><em>x</em><em> </em><em><u>-</u></em><em><u> </u></em><em><u>1</u></em><em><u>2</u></em><em><u> </u></em>
Answer:
Step-by-step explanation:
<u>Arithmetic Sequences
</u>
The arithmetic sequences are identified because any term n is obtained by adding or subtracting a fixed number to the previous term. That number is called the common difference.
The equation to calculate the nth term of an arithmetic sequence is:
Where
an = nth term
a1 = first term
r = common difference
n = number of the term
The sum of the n terms of an arithmetic sequence is given by:
We are given the first two terms of the sequence:
a1=5, a2=8. The common difference is:
r = 8 - 5 = 3
Thus the general term of the sequence is:
The formula for the sum is:
Operating:
<h3>
Answer: 5/6</h3>
Apply the square root to 25/36, which is the same as square rooting each piece of the fraction
sqrt(25) = 5
sqrt(36) = 6
Put another way, you can think of it in reverse:
(5/6)^2 = (5/6)*(5/6) = (5*5)/(6*6) = (5^2)/(6^2) = 25/36
Answer: -3
Step-by-step explanation:
-3x+ 7x+ 35= 5x + 38
You solve the distributive property on the left side and set it equal to the right
4x+35= 5x+38
-4x -4x
35= x+38
-38 -38
X=-3
Answer:
A'(0,0) and B'(0,7.5) and C'(12.5,7.5) and D'(12.5,0)
Step-by-step explanation:
<u><em>Find the coordinates of the point after dilation</em></u>
A'(0,0) and B'(0,7.5) and C'(12.5,7.5) and D'(12.5,0)
<em>I hope this helps you</em>
<em>:)</em>