Answer:
First you need to get your variable(x) by itself.
You do that by adding 16 to both sides of the greater than sign.
The 16 cancels or goes away. and 16 + 4 =20.
Your new equation is 20<4x
Finally you divide 20 by 4 to get 5
Your answer is 5<x or x>5.
Answer:
C
Step-by-step explanation:
Calculate AC using Pythagoras' identity in ΔABC
AC² = 20² - 12² = 400 - 144 = 256, hence
AC =
= 16
Now find AD² from ΔACD and ΔABD
ΔACD → AD² = 16² - (20 - x)² = 256 - 400 + 40x - x²
ΔABD → AD² = 12² - x² = 144 - x²
Equate both equations for AD², hence
256 - 400 + 40x - x² = 144 - x²
-144 + 40x - x² = 144 - x² ( add x² to both sides )
- 144 + 40x = 144 ( add 144 to both sides )
40x = 288 ( divide both sides by 40 )
x = 7.2 → C
26< any number larger than 26 (whole numbers and fractions/decimals)
Hey there! :)
The formula for finding area of circles is: π · r²
<em>Remember that radius is half the diameter. To find radius when the diameter is given, divide by 2</em>
d = 26
26 ÷ 2 = 13
_____________________________________________________________
π · r²
r = 13
13² = 13 × 13 = 169
169 × 3.14 = 530.66 = 530.7
The area of the swimming pool is 530.7 ft²
Hope this helps :)
<h2>
Explanation:</h2><h2>
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Hello! Remember you have to write complete questions in order to get good and exact answers. Here you forgot to write the relation so I could help you providing my own relation.
Remember that for any relation, we have a set
that matches the the domain (also called the set of inputs) of the function and the set
that contains the range (also called the set of outputs).
Suppose our relation is:

So the x-values represents the set A and the y-values the set B. Therefore, by evaluating the x-values into our relation we get:

So in this context, the correct option is:
B) (-9,-8, -7, -6, -5}