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2 years ago

A bag can hold 1 1/2pounds of flour. if Mimi has 7 1/2pounds of flour, then how many bags of flour can Mimi make?

Mathematics

2 answers:

Naily [24]2 years ago

6 0

Answer:

5 BAGS OF FLOUR

7 1/2 ÷ 1 1/2 = 5

Based on the given conditions, formulate: 7 1/2 / 1 1/2 Find common denominator and write the numeral.

umka21 [38]2 years ago

4 0

Answer:

7 1/2 ÷ 1 1/2

make them improper fractions;

15/2 ÷ 3/2

make 3/2 a reciprocal(basically flipping the fraction upside down)

15/2 ÷ 2/3

and multiply across;

15/2 x 2/3 = 30/6 which simplifies to 5 bags of flour.

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you rent an apartment that costs $1600 per month during the first year ,but the rent is set to go up 11.5% per year.what would b

RoseWind [281]

Answer:

$4,750.

Step-by-step explanation:

To determine the rental value of the apartment in the tenth year, knowing that it is worth 1,600 during the first year but that it will be adjusted annually to 11.5%, the following calculation must be made:

X = 1,600 x (1 + 0.115) ^ 10

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2 years ago

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Help me ASAP please

Montano1993 [528]

Answer: i feel that the coorect answer is b

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3 years ago

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The length of a table is 6 feet. On a scale drawing, the length is 2 inches. Write three possible scales for the drawing.

Rus_ich [418]

A possible scale for the drawing can be
1 inches : 3 feet.
2 inches : 6 feet
or 3 inches to 9 feet
or 0.5 inches to 1.5 feet.

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2 years ago

A survey of 90 men found that an average amount spent on St. Patrick's day of $55 with a standard deviation of $18. A similar su

dem82 [27]

Answer:

The value of the test statistic is 4.70.

Step-by-step explanation:

The hypothesis for this test can be defined as follows:

H₀: Men do not spend more than women on St. Patrick's day, i.e. μ₁ = μ₂.

Hₐ: Men spend more than women on St. Patrick's day, i.e. μ₁ > μ₂.

The population standard deviations are not known.

So a t-distribution will be used to perform the test.

The test statistic for the test of difference between mean is:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }$

Given:

$\bar x_{1}=55\\s_{1}=18\\n_{1}=90\\\bar x_{1}=44\\s_{1}=16\\n_{1}=86$

Compute the value of the test statistic as follows:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }=\frac{55-44}{\sqrt{\frac{15^{2}}{90}+\frac{16^{2}}{86} }}=4.70$

Thus, the value of the test statistic is 4.70.

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3 years ago

Find the quotient. 5/6 divided by 1/6

Montano1993 [528]

Answer:

5 × 6

6 × 1

30 ÷ 6

6 ÷ 6

= 5

the awnser would be 5

Step-by-step explanation:

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2 years ago

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