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2 years ago

A rectangle has a length of 3x-5 and a width of 2x+9.

Mathematics

1 answer:

Montano1993 [528]2 years ago

8 0

Step-by-step explanation:

l = 3x - 5

w = 2x + 9

perimeter = 2l + 2w = 2(3x - 5) + 2(2x + 9) =

= 6x - 10 + 4x + 18 = 10x + 8

area = l×w = (3x - 5)(2x + 9) = 6x² + 27x - 10x - 45 =

= 6x² + 17x - 45

You might be interested in

Which shows one way to determine the factors of y3 – 9x2 + 5x – 45 by grouping

Gnoma [55]

Answer:

(x²+5)(x-9)

Step-by-step explanation:

Assuming that you are asking to factor by grouping:

x³ - 9x² + 5x – 45

You can group:

x²(x-9) + 5(x-9)

and then combine the x² and 5:

(x²+5)(x-9)

4 0

2 years ago

Find the magnitude of WX for W(-2, 8, -3) and X(1, 4, -1)

zheka24 [161]

The magnitude of WX is $\sqrt{29}$ ⇒ c

Step-by-step explanation:

The magnitude of XY (its length) where,

$X=(x_{1},y_{1},z_{1})$
$Y=(x_{2},y_{2},z_{2})$

is IXYI = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}+(z_{2}-z_{1})^{2}}$

∵ W = (-2 , 8 , -3)

∵ X = (1 , 4 , -1)

- To find the magnitude of WX use the formula above

∴ $x_{1}$ = -2 and $x_{2}$ = 1

∴ $y_{1}$ = 8 and $y_{2}$ = 4

∴ $z_{1}$ = -3 and $z_{2]$ = -1

- Substitute these values in the rule above

∵ IWXI = $\sqrt{(1--2)^{2}+(4-8)^{2}+(-1--3)^{2}}=\sqrt{9+16+4}$

∴ IWXI = $\sqrt{29}$

The magnitude of WX is $\sqrt{29}$

Learn more:

You can learn more about the position of an object in brainly.com/question/10940255

#LearnwithBrainly

8 0

3 years ago

Read 2 more answers

I don't know how to do this one. plz help

egoroff_w [7]

Answer:

As x decreases without bound, f(x) increases without bound

As x increases without bound, f(x) approaches 0

Step-by-step explanation:

As x gets more and more negative f(x) gets bigger and bigger

f(x) = (7/10) ^ x but x is negative so flip it and then x is a larger number

(10/7) ^ large number so it will get larger

as → -∞ f(x) →∞

As x gets more and more positive f(x) gets smaller and smaller

f(x) = (7/10) ^ x closer and closer to 0. The denominator gets larger faster than the numerator = 1 / large number

as → ∞ f(x) →0

3 0

2 years ago

If sin theta = -1/2 and lies in the third quadrant, what is the cos?

never [62]

Sin angle that equals the 1/2 value is the 30 degree on the 1st Quadrant.

The angle of 30 degree on the 3rd Quadrant is equivalent to (formula and circle in the 1st photo) 180 + 30 = 210°.

So theta = 210° (3rd Quadrant) = 30° (1st Quadrant).

$cos \: 30\degree = \sqrt{3} \div 2$

Now just transfer the cos 30° to the 3rd Quadrant and the signal will be negative (as shown in the 2nd photo attached).

$cos \: 210 \degree = - \sqrt{3} \div 2$

5 0

3 years ago

A video company randomly selected 100 of its subscribers and asked them how many hours of shows they watch per week. Of those su

Alik [6]

Answer:

1,135 people

For every 100 people only 45 people watch more than 10 hours per week. So, the ratio is (45/100), since the company has 2500 we want to know what (x/2500) is. The total ratio becomes (1,135/2,500).

The number is found by dividing 2500 by 100 to receive the common factor of 25. You multiply 45 by 25 to receive your total answer.

Step-by-step explanation:

For every 100 people only 45 people watch more than 10 hours per week. So, the ratio is (45/100), since the company has 2500 we want to know what (x/2500) is. The total ratio becomes (1,135/2,500).

The number is found by dividing 2500 by 100 to receive the common factor of 25. You multiply 45 by 25 to receive your total answer.

8 0

3 years ago