I’m assuming the answer is HL since they only gave us two letters.
Answer:
The answer is b because you are taking away from susan
Step-by-step explanation:
Answer:
(0.767,0.833)
Step-by-step explanation:
The 95% confidence interval for population proportion p can be computed as
![p-z_{\frac{\alpha }{2} } \sqrt{\frac{pq}{n} }](https://tex.z-dn.net/?f=p-z_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%20%5Csqrt%7B%5Cfrac%7Bpq%7D%7Bn%7D%20%7D%20%20%3CP%3Cp%2Bz_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%20%5Csqrt%7B%5Cfrac%7Bpq%7D%7Bn%7D%20%7D)
The z-value associated with 95% confidence level is 1.96.
whereas p=x/n
We are given that x=440 and n=550.
p=440/550=0.8
![0.8-1.96\sqrt{\frac{0.8(0.2)}{550} }](https://tex.z-dn.net/?f=0.8-1.96%5Csqrt%7B%5Cfrac%7B0.8%280.2%29%7D%7B550%7D%20%7D%20%20%3CP%3C0.8%2B1.96%5Csqrt%7B%5Cfrac%7B0.8%280.2%29%7D%7B550%7D%20%7D)
![0.8-1.96\sqrt{\frac{0.16}{550} }](https://tex.z-dn.net/?f=0.8-1.96%5Csqrt%7B%5Cfrac%7B0.16%7D%7B550%7D%20%7D%20%20%3CP%3C0.8%2B1.96%5Csqrt%7B%5Cfrac%7B0.16%7D%7B550%7D%20%7D)
![0.8-1.96\sqrt{0.00029 }](https://tex.z-dn.net/?f=0.8-1.96%5Csqrt%7B0.00029%20%7D%20%20%3CP%3C0.8%2B1.96%5Csqrt%7B0.00029%20%7D)
![0.8-1.96(0.01706)](https://tex.z-dn.net/?f=0.8-1.96%280.01706%29%20%3CP%3C0.8%2B1.96%280.01706%29)
![0.8-0.03343](https://tex.z-dn.net/?f=0.8-0.03343%20%3CP%3C0.8%2B0.03343)
![0.76657](https://tex.z-dn.net/?f=0.76657%20%3CP%3C0.83343)
Thus, the required confidence interval is
0.767<P<0.833 (rounded to 3 decimal places)
Hence, we are 95% confident that our true population proportion will lie in the interval (0.767,0.833)
So 2/7 cookies on Monday
n 1/3 more on Tuesday
so we are going to fine Tuesday's amount , to find what fraction did Gail sell on the two days
so
2/7 + 1/3
find lCM which is 21
u add and get 13/21
so
31/21+2/7=19/21
14.99*.12=1.80
14.99-1.8=13.19
13.19*.0625=.94
13.19+.94=14.13
final price 14.13