R is the midpoint of PQ. PR = 6x + 7 and RQ = 3x + 8, find the length of PQ.

Mathematics

1 answer:

Ksivusya [100]2 years ago

6 0

Answer:

PQ = 18

Step-by-step explanation:

If R is the midpoint of PQ, then PR = RQ

⇒ 6x + 7 = 3x + 8

⇒ 3x = 1

⇒ x = 1/3

So PR = 6x + 7 = 6(1/3) + 7 = 9

and RQ = 3x + 8 = 3(1/3) + 8 = 9

⇒ PQ = PR + RQ = 9 + 9 = 18

You might be interested in

Which theorem or postulate justifies this statement? angle6 cong angle13

dezoksy [38]

Answer:

C. Alternate Exterior Angles Theorem

Step-by-step explanation:

I took the test

8 0

3 years ago

Simplify 2x^2+6x-7x+8-3x^2+1

Doss [256]

$(((((2*(x^2))+6x)-7x)+8)-3x^2)+1 \\ \\ ((((2x^2 + 6x) - 7x) + 8) - 3x^2) + 1 \\ \\ we \ would \ then \ (pull \ out) \ like \ terms. \\ \\ -x^2 - x + 9 = -1 * (x^2 + x - 9) \\ \\ \left[\begin{array}{ccc} -9 + 1 = -8 \\
 -3 + 3 = 0 \\
 -1 + 9 = 8 \\
\end{array}\right] \\ \\ Your \ answer: \boxed{\boxed{\bf{ -x^2 - x + 9
}}}$

I hope this helps you!

3 0

3 years ago

Read 2 more answers

Which expression is equivalent to -7(y - 2)

Neko [114]

The expression equivalent to -7(y - 2) is -7y + 14

<h3>Which expression is equivalent to -7(y - 2)?</h3>

Given the expression; -7(y - 2)

We expand the expression by multiplying each element inside the parentheses the element out i.e -7

-7(y - 2)

[ -7 × y and -7 × -2 ]

-7y + 14