Answer:
Neighborhood Q appears to have a bigger family size
Step-by-step explanation:
Mean = the sum of all data values divided by the total number of data values
Number of families in Neighborhood Q = 9
Mean family size of Neighborhood Q:
= (2 + 5 + 4 + 3 + 2 + 5 + 3 + 6 + 5) ÷ 9
= 35 ÷ 9
= 3.888888...
Number of families in Neighborhood S = 9
Mean family size of Neighborhood S:
= (2 + 3 + 2 + 3 + 7 + 2 + 3 + 3 + 2) ÷ 9
= 27 ÷ 9
= 3
The mean family size of Neighborhood Q is 3.88.. and the mean family size of Neighborhood S is 3. Therefore, Neighborhood Q appears to have a bigger family size as it's average family size is bigger than that of Neighborhood S.
Answer:
1. ridescost+admission=total
if x=number of tickets and y is total and cost per ride is 1.25 then
1.25x+admission=y
if we solve
when x=25, y=43.75
1.25(25)+admission=43.75
31.25+admission=43.75
minus 31.25 from both sides
admission=12.50
a.
y=1.25x+12.5
b.
x is number of tickets and y is total cost
c. math, seriously, just read what is above option a (the one in the top of the answer)
if you're too lazy then:
ridescost+admission=total
if x=number of tickets and y is total and cost per ride is 1.25 then
1.25x+admission=y
if we solve
when x=25, y=43.75
2.
(a)
m = (y2 - y1) / (x2 - x1) = (4 - 9)/(-2 - 8) = -5/(-10) = 1/2
(b)
y - y1 = m(x - x1)
Using the first given point,
y - 9 = (1/2)(x - 8)
Using the second given point,
y - 4 = (1/2)(x + 2)
note they both simplify to
y = (1/2)x + 5
(c)
y = (1/2)x + 5
3.
Answer:
mi no hablar espanol.
Step-by-step explanation:
Let S be the first side.
Longest side is then 2S.
Third side is 2S-10.
Perimeter is sum of all three sides = S+2S+2S-10 = 75
=>
5S-10=75
5S=75+10=85
S=17
Therefore
S=17 is the first side.
Longest side is then 2S=2*17=34.
Third side is 2S-10=2*17-10=24.
Answer:750
Step-by-step explanation:
because you need to find the area of 1 tile then multiply it by 100