Answer:
First of all draw a base line
then, get a compass and extend it as needed for the base of triangle
after that, adjust the length of compass to 2 cm approximately
then at both end points of base draw angle of 60° to 75° ( because you asked for a larger triangle )
then draw out a straight line from the angle you made and intersect both of the lines then you get the third point.
Now, boom your triangle is ready..
One way to do this problem is to take 26.65 and divide it by all of the values from $2.01 to $2.99. If one of these goes in evenly with no remainder then that is the cost of each notepad. The quotient (answer when you divide) is the number of pads. Since we can’t have half a pad, the number must go in evenly (leave no remainder).
While we can check each of these, I noticed that 26.65 ends in a 5 and so is divisible by 5 so I decided to check 2.05 as a possible price and it went in evenly. The quotient is 13.
thus, there were 13 notepads and the cost of each is $2.05
Option C:
![2 g^{3}-5 g^{2}+6](https://tex.z-dn.net/?f=2%20g%5E%7B3%7D-5%20g%5E%7B2%7D%2B6)
Solution:
Given expression:
![$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5Cleft%285%20g%5E%7B4%7D%2B5%20g%5E%7B3%7D-17%20g%5E%7B2%7D%2B6%20g%5Cright%29-%5Cleft%283%20g%5E%7B4%7D%2B6%20g%5E%7B3%7D-7%20g%5E%7B2%7D-12%5Cright%29%7D%7Bg%2B2%7D)
To find which expression is equal to the given expression.
![$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5Cleft%285%20g%5E%7B4%7D%2B5%20g%5E%7B3%7D-17%20g%5E%7B2%7D%2B6%20g%5Cright%29-%5Cleft%283%20g%5E%7B4%7D%2B6%20g%5E%7B3%7D-7%20g%5E%7B2%7D-12%5Cright%29%7D%7Bg%2B2%7D)
Expand the term ![-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right):-3 g^{4}-6 g^{3}+7 g^{2}+12](https://tex.z-dn.net/?f=-%5Cleft%283%20g%5E%7B4%7D%2B6%20g%5E%7B3%7D-7%20g%5E%7B2%7D-12%5Cright%29%3A-3%20g%5E%7B4%7D-6%20g%5E%7B3%7D%2B7%20g%5E%7B2%7D%2B12)
![$=\frac{5 g^{4}+5 g^{3}-17 g^{2}+6 g- 3 g^{4}-6 g^{3}+7 g^{2}+12}{g+2}](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B5%20g%5E%7B4%7D%2B5%20g%5E%7B3%7D-17%20g%5E%7B2%7D%2B6%20g-%203%20g%5E%7B4%7D-6%20g%5E%7B3%7D%2B7%20g%5E%7B2%7D%2B12%7D%7Bg%2B2%7D)
Arrange the like terms together.
![$=\frac{5 g^{4}- 3 g^{4}+5 g^{3}-6 g^{3}-17 g^{2}+7 g^{2}+6 g+12}{g+2}](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B5%20g%5E%7B4%7D-%203%20g%5E%7B4%7D%2B5%20g%5E%7B3%7D-6%20g%5E%7B3%7D-17%20g%5E%7B2%7D%2B7%20g%5E%7B2%7D%2B6%20g%2B12%7D%7Bg%2B2%7D)
![$=\frac{2 g^{4}- g^{3}-10 g^{2}+6 g+12}{g+2}](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B2%20g%5E%7B4%7D-%20g%5E%7B3%7D-10%20g%5E%7B2%7D%2B6%20g%2B12%7D%7Bg%2B2%7D)
Factor the numerator ![2 g^{4}-g^{3}-10 g^{2}+6 g+12=(g+2)\left(2 g^{3}-5 g^{2}+6\right)](https://tex.z-dn.net/?f=2%20g%5E%7B4%7D-g%5E%7B3%7D-10%20g%5E%7B2%7D%2B6%20g%2B12%3D%28g%2B2%29%5Cleft%282%20g%5E%7B3%7D-5%20g%5E%7B2%7D%2B6%5Cright%29)
![$=\frac{(g+2)\left(2 g^{3}-5 g^{2}+6\right)}{g+2}](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B%28g%2B2%29%5Cleft%282%20g%5E%7B3%7D-5%20g%5E%7B2%7D%2B6%5Cright%29%7D%7Bg%2B2%7D)
Cancel the common factor g + 2, we get
![=2 g^{3}-5 g^{2}+6](https://tex.z-dn.net/?f=%3D2%20g%5E%7B3%7D-5%20g%5E%7B2%7D%2B6)
Hence option C is the correct answer.
Answer:
the greatest number of baskets Pam van make is 6
0.1/0.5 is the same as 1/5
1/5 = X/10
we times both sides by 10 to get x on its own
1/5 x 10 = 10/5 = 2 ( which equals X/10 x 10)
X/10 x 10 = X
2 = X