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ohaa [14]
3 years ago
15

Explain how to modify the graphs of f(x) and g(x) to graph the solution set to the following system of inequalities. How can the

solution set be identin
y < x^2 - 3
y > x^2 + 2

Mathematics
1 answer:
Norma-Jean [14]3 years ago
7 0

The graphs of f(x) and g(x) are transformed function from the function y = x^2

The set of inequalities do not have a solution

<h3>How to modify the graphs</h3>

From the graph, we have:

f(x) = x^2 -3 and g(x) = -x^2 +2

To derive y < x^2 - 3, we simply change the equality sign in the function f(x) to less than.

To derive y > x^2 + 2, we perform the following transformation on the function g(x)

  • Shift the function g(x) down by 2 units
  • Reflect across the x-axis
  • Shift the function g(x) down by 3 units
  • Change the equality sign in the function g(x) to greater than

<h3>How to identify the solution set</h3>

The inequalities of the graphs become

y < x^2 - 3 and y > x^2 + 2

From the graph of the above inequalities (see attachment), we can see that the curves of the inequalities do not intersect.

Hence, the set of inequalities do not have a solution

Read more about inequalities at:

brainly.com/question/25275758

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W is the midpoint of VX and Z is the midpoint of VY . If XY=p and WZ=p–30, what is WZ?
juin [17]

\large{ \tt{❃ \: EXPLANATION}} :

  • You'll have to know : Mid-point theorem states that A straight line segment joining the mid-points of any two triangle is parallel to the third side and it is equal to half of the length of the third side.

  • We're provided : XY = p , WZ = p - 30 & we're asked to find out the value of WZ. For that , firstly we have to find out the value of p.

\large{ \tt{❁ \: LET'S \: START }: }

  • Set up an equation & solve for p :

\large{ \bf{☄ \: p  - 30 =  \frac{1}{2}  p }}

\large{ \tt{↦ \frac{1}{2} p = p - 30}}

\large{ \tt{↦ \frac{1}{2} p - p =  - 30}}

\large{ \tt{↦ \frac{p - 2p}{2} =  - 30 }}

\large{ \tt{↦p - 2p =  - 60}}

\large{ \tt{ ↦ \: - p =  - 60}}

\large{ \tt{↦p = 60}}

  • The value of p is 60

\large{ \tt{❇ \: REPLACING \: VALUE}} :

\large{ \tt{↬ \: wz = p - 30 =  60 - 30 =   \boxed{\boxed{ \tt{30 }} }✔}}

  • Hence , WZ = 30 .

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5a + 5b -5 + 11a - 11b + 11​
tino4ka555 [31]

Answer:

16a - 6b + 6

Step-by-step explanation:

5a + 5b - 5 + 11a - 11b + 11 = 5a + 11a + 5b - 11b - 5 + 11 = 16a - 6b + 6

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Write an equation in which the quadratic expression 2x^2-2x-13 equals 0
torisob [31]

Answer:

x = 3 and -2 are the two solutions.

Step-by-step explanation:

2x^2 -2x -12 = 0

First factor out a 2

2(x^2 - x - 6) = 0

2(x - 3)(x + 2) = 0

2 = 0 x - 3 = 0 x + 2 = 0

2 does not equal zero so this is an extraneous solution

x - 3 = 0 so x = 3

x + 2 = 0 so x = -2

8 0
3 years ago
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