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adoni [48]
3 years ago
15

Find an equation of the line that bisects the acute angles formed by the lines with equations 2x+y-5=0 and 3x-2y+6=0

Mathematics
1 answer:
Neko [114]3 years ago
5 0
The solving for the first one should be like this 

2x+y-5/sqrt 2^2 1^2=2x+y-5/sqrt5
And the next part 3x-2y+6/sqrt 3^2 -2^2=3x-2y+6/sqrt13

After these manipulations just multiply them 

(2sqrt13-3sqrt5)x+(sqrt13+2sqrt5) y-5sqrt13-6sqrt5=0 

And finally you need to square and simplify for the completed answer
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