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3 years ago

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Find an equation of the line that bisects the acute angles formed by the lines with equations 2x+y-5=0 and 3x-2y+6=0

1 answer:

Neko [114]3 years ago

5 0

The solving for the first one should be like this

$2x+y-5/sqrt 2^2 1^2=2x+y-5/sqrt5$
And the next part $3x-2y+6/sqrt 3^2 -2^2=3x-2y+6/sqrt13$

After these manipulations just multiply them
$
(2sqrt13-3sqrt5)x+(sqrt13+2sqrt5) y-5sqrt13-6sqrt5=0 
$
And finally you need to square and simplify for the completed answer

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Step-by-step explanation:

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From a group of 12 students, we want to select a random sample of 4 students to serve on a university committee. How many combin

borishaifa [10]

Answer:

495 combinations of 4 students can be selected.

Step-by-step explanation:

The order of the students in the sample is not important. So we use the combinations formula to solve this question.

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