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mestny [16]
3 years ago
10

Can someone please help me!?

Mathematics
1 answer:
Lelechka [254]3 years ago
8 0
Your answer would be  8, i recommend a website called desmos for graphing online 
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Find the greatest number which divides by 1280 and 1371 leaves a remainder in each case?
vladimir1956 [14]
1279???
Because the gcf does not leave any remainders behind. The gcf could be 1280, but that would not leave a remainder behind if you divided 1280 by 1280. So, I think it is 1279, but i am probably wrong
4 0
3 years ago
Read 2 more answers
RBT/Z + H/K = M, Solve for H
irakobra [83]

Answer:

  • H = MK - RBTK/Z

Step-by-step explanation:

<u>Given</u>

  • RBT/Z + H/K = M

<u>Solving for H</u>

  • RBT/Z + H/K = M
  • K×RBT/Z + K×H/K = K×M                     ⇒ <em>multiplying all terms by K to clear fraction</em>
  • RBTK/Z + H = MK
  • RBTK/Z + H - RBTK/Z= MK - RBTK/Z   ⇒ <em>subtracting RBTK/Z from both sides</em>
  • H = MK - RBTK/Z
6 0
4 years ago
What is the probability that a domestic airfare is $550 or more (to 4 decimals)?
Korvikt [17]
All I know is look it up because you are in college and I am in elementary school almost to middle.
5 0
3 years ago
At 9 AM there are 37 bacteria in a dish and they start doubling every 15 minutes. At t = 274 minutes an
givi [52]

Answer:

5,035,041

Step-by-step explanation:

Exponential growth:

y = a(1 + r)^{x}

y = future amount

a = initial amount

r = growth rate

x = number of periods

Part A: growth at the rate of doubling each 15 minutes for 274 minutes

Each period is 15 minutes.

a = 37

x = 274/15 = number of periods

r = 100%

y = 37(1 + 1)^{\frac{274}{15}

-------------------------------------------------------------------------------------

Exponential decay:

y = a(1 - r)^{x}

The growth takes place from 9 AM for 274 minutes, or 4 hours and 34 minutes, until 1:34 PM. The decay goes from 1:34 PM to 7 PM, or 5 hours and 26 minutes, or 326 minutes

Part B: decay at the rate of 6% each 24 minutes for 326 minutes

y = 37(1 + 1)^{\frac{274}{15}}(1 - 0.06)^{\frac{326}{24}}

y = 5035041

Answer: 5,035,041

8 0
3 years ago
Evaluate 6j 23 kl−3, when j=3, k=7, and l=33.
Katyanochek1 [597]
To evaluate the expression given above, we just have to substitute the values assigned to each variable in the expression. The expression would be:

<span>6j23kl−3

We evaluate as follows:

</span><span>6j 23 kl−3
6(3)(23)(7)(33) - 3
95631

Hope this answers the question. Have a nice day.
</span>
3 0
4 years ago
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