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Mashcka [7]
3 years ago
5

Find the greatest number which divides by 1280 and 1371 leaves a remainder in each case?

Mathematics
2 answers:
vladimir1956 [14]3 years ago
4 0
1279???
Because the gcf does not leave any remainders behind. The gcf could be 1280, but that would not leave a remainder behind if you divided 1280 by 1280. So, I think it is 1279, but i am probably wrong
labwork [276]3 years ago
3 0
294
is it hope i helped


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Find the integral using substitution or a formula.
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\rm \int \dfrac{x^2+7}{x^2+2x+5}~dx

Derivative of the denominator:
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and then split the fraction,

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Based on our previous test, we know that a simple substitution will work for the first integral: \rm \quad u=x^2+2x+5\qquad\to\qquad du=2x+2~dx

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integrating to a log,

\rm ln|x^2+2x+5|+\int\dfrac{5}{x^2+2x+5}~dx

Other one is a little tricky. We'll need to complete the square on the denominator. After that it will look very similar to our arctangent integral so perhaps we can just match it up to the identity.

\rm x^2+2x+5=(x^2+2x+1)+4=(x+1)^2+2^2

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Let's factor the 5 out of the intergral,
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\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\frac{(x+1)^2}{2^2}+1}~dx

Bringing all that stuff together as a single square,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(\dfrac{x+1}{2}\right)^2+1}~dx

Making the substitution: \rm \quad u=\dfrac{x+1}{2}\qquad\to\qquad 2du=dx

giving us,

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simplying a lil bit,

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and hopefully from this point you recognize your arctangent integral,

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undo your substitution as a final step,
and include a constant of integration,

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Hope that helps!
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