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Masja [62]
3 years ago
9

Find jh in triangle HIJ

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
5 0

Answer:

JH=16

Step-by-step explanation:

Hi there!

We are given ΔHIJ, where HI is parallel to KL, and that JK=10, JI=40, and JL=25

We want to find JH

We can use something called the Triangle Proportionality Theorem to help us find JH

The Triangle Proportionality Theorem essentially states that if there is a line parallel to one of the sides of a triangle that intersects the other 2 sides of that triangle, then that segment divides those sides proportionally

In other words, KL is parallel to HI and intersects both HJ and JI, and JK, JH, JL, and JI create a proportion, which is \frac{JK}{JH} =\frac{JL}{JI}

We can substitute the values that we know into that equation

\frac{10}{JH} =\frac{25}{40}

We can simplify 25/40 to 5/8.

\frac{10}{JH} =\frac{5}{8}

Now we can cross multiply (use the means-extreme theorem)

Multiply 10 and 8 together, and set that equal to 5 times JH

80 = 5JH
Divide both sides by 5

16=JH
Hope this helps!
See more on the Triangle Proportionally Theorem here: brainly.com/question/20064024

Daniel [21]3 years ago
3 0

Answer:

2

2 \times area \div height \:

Step-by-step explanation:

the answer is 5

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<em><u>Solution:</u></em>

We have to find the equation of the line that passes through the points 7, -4 and -1, 3

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The point slope form is given as:

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m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Substituting (x_1 , y_1 ) = (7, -4) \text{ and } (x_2, y_2) = (-1, 3)

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y - (-4) = \frac{-7}{8}(x - 7)\\\\y + 4 = \frac{-7}{8}(x - 7)

Thus the point slope form is found when point (7, -4) is used

<h3><u>Slope intercept form:</u></h3>

The slope intercept form is given as:

y = mx + c  ----- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Substitute m = -7/8 and (x, y) = (7, -4) in eqn 1

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Substitute m = -7/8 and c = \frac{17}{8} in eqn 1

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