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finlep [7]
3 years ago
10

write the equation of the line that passes through the points 7, -4 and -1, 3 first and point-slope form and then in slope inter

cept form. The slope of the line is? When the point 7, -4 is used, the point of the slope form of the line is? The slope intercept form of the line is?
Mathematics
2 answers:
anyanavicka [17]3 years ago
8 0

The slope of line is \frac{-7}{8}

The point slope form is found when point (7, -4) is used is y + 4 = \frac{-7}{8}(x - 7)

The slope intercept form is y = \frac{-7}{8}x + \frac{17}{8}

<em><u>Solution:</u></em>

We have to find the equation of the line that passes through the points 7, -4 and -1, 3

<h3><u>Point slope form:</u></h3>

The point slope form is given as:

y - y_1 = m(x - x_1)

Where "m" is the slope of line

Given two points are (7, -4) and (-1, 3)

<h3><u>Let us find the slope of line</u></h3>

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Substituting (x_1 , y_1 ) = (7, -4) \text{ and } (x_2, y_2) = (-1, 3)

m=\frac{3-(-4)}{-1-7}=\frac{7}{-8}

m=\frac{-7}{8}

Thus slope of line is found

Substitute value of m and point (7, -4) in eqn 1

y - (-4) = \frac{-7}{8}(x - 7)\\\\y + 4 = \frac{-7}{8}(x - 7)

Thus the point slope form is found when point (7, -4) is used

<h3><u>Slope intercept form:</u></h3>

The slope intercept form is given as:

y = mx + c  ----- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Substitute m = -7/8 and (x, y) = (7, -4) in eqn 1

-4 = \frac{-7}{8}(7) + c\\\\-32 = -49 + 8c\\\\8c = 17\\\\c = \frac{17}{8}

Substitute m = -7/8 and c = \frac{17}{8} in eqn 1

y = \frac{-7}{8}x + \frac{17}{8}

Thus the required equation of line is found

BabaBlast [244]3 years ago
8 0

Answer:

<u>Quick Answer</u>

1. -7/8

2. y+4= (-7/8)(x-7)

3. y=(-7/8)x+(17/8)

Step-by-step explanation:

I just answered this on edg.

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