Choose the best graph that represents the following systems of linear inequality.

Geraldo has a coupon for $12 off the total bill at a local restaurant. Geraldo does not want to spend more than $65. The inequal

Trava [24]

In here, we could write an equality as x – 12 < 65. In solving inequalities, we follow the same rule as solving algebraic expressions. We will transpose 12 to the other side, giving us x < 65 + 12. Simplifying, we have x < 77. Geraldo must have a bill less than $77 in order for him not to spend more than $65.

3 0

4 years ago

Read 2 more answers

Work out the circumference of the circle when the radius is 6mm and give the answer in terms of pie.

s344n2d4d5 [400]

_______________________________

Hey!!

Solution,

Radius(r)= 6 mm

Circumference of circle=?

Now,

Circumference of circle=2 pie r

 =2*pi*6

 =12 pie

So the answer is 12 pie.

Hope it helps...

Good luck on your assignment

______________________________

4 0

3 years ago

What do you add to 2 2/9 to make 4

shutvik [7]

Answer:

1 7/9

Step-by-step explanation:

3 0

3 years ago

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Solve the equation by completing the square

Nana76 [90]

Answer:

s = - 1 ± $\sqrt{7}$

Step-by-step explanation:

Given

s² + 2s - 6 = 0 ( add 6 to both sides )

s² + 2s = 6

To complete the square

add ( half the coefficient of the s- term )² to both sides

s² + 2(1)s + 1 = 6 + 1

(s + 1)² = 7 ( take the square root of both sides )

s + 1 = ± $\sqrt{7}$ ( subtract 1 from both sides )

s = - 1 ± $\sqrt{7}$

Thus

s = - 1 - $\sqrt{7}$ , s = - 1 + $\sqrt{7}$

4 0

3 years ago

△ABC is a right isosceles triangle, the centers of two arcs are the midpoint of AB

mel-nik [20]

Answer:

0

Step-by-step explanation:

Let's define 3 areas:

S = area of semicircle with radius 6 in (diameter AB)
T = area of quarter circle with radius 6√2 in (radius AC)
U = area of triangle ABC (side lengths 6√2)

The white space between the "moon" and the triangle has area ...

white = T - U

Then the area of the "moon" shape is ...

moon = S -white = S -(T -U) = S -T +U

The area we're asked to find is ...

moon - triangle = (S -T +U) -U = S -T

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The formula for the area of a circle of radius r is ...

A = πr²

So, ...

S = (1/2)π(6 in)² = 18π in²

and

T = (1/4)π(6√2 in)² = 18π in²

The difference in areas is S -T = (18π in²) -(18π in²) = 0.

There is no difference between the areas of the "moon" and the triangle.

4 0

3 years ago