Answer:
BC < ED ⇒ answer A
Step-by-step explanation:
* Lets revise some facts in the triangle
- If one side of a triangle is longer than another side, then the angle
opposite the longer side will be larger than the angle opposite the
shorter side
- If one angle in a triangle is larger than another angle in a triangle,
then the side opposite the larger angle will be longer than the side
opposite the smaller angle
* Lets solve the problem
- In the two triangles BCD and DEB
∵ CD = 8 and BE = 8
∴ CD = BE
∵ Side BD is a common side in the two triangles
- The third side in Δ BCD is BC and the third side in DEB is DE
∵ BC is the opposite side to the angle of measure 24°
∵ ED is the opposite side to the angle of measure 30°
∵ The measure 24° < the measure 30°
∴ The side opposite to the angle of measure 24° < the side opposite
to the angle of measure 30°
∵ The other two sides of the 2 triangles BCD and DEB are equal
∴ We can compare between the 3rd sides in the Δ BCD and Δ DEB
∴ BC < ED
We must solve <span>2/5 ≥ w -3/5. Note that w is already +, so leave it where it now is. Add 3/5 to both sides of this inequality:
2/5 + 3/5 </span>≥ w - 3/5 + 3/5
Then: 1 ≥ w, or w ≤ 1 (answer)
Step-by-step explanation:
-3y=12+3x
-y=4+x
y=-4-x and m which is the gradient is the coefficient of x which is -1, therefore m=-1
Answer:
No, it doesn't pass the vertical line test.
Answer:
See explanation
Step-by-step explanation:
Maximum weight = 20 kg
Bag 1 = 3.5kg
Bag 2 = 15 kg
Bag 3 = 2kg
Bag 4 = 1.5kg
Total weight of bags = 22 kg
Excess weight of his luggage = Total weight of bags - Maximum weight
= 22 kg - 20 kg
= 2 kg
Express the excess weight as a percentage of his maximum weight allowed = excess weight / maximum weight × 100
= 2/20 × 100
= 0.1 × 100
= 10%
Express the excess weight as a percentage of his maximum weight allowed = 10%