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miskamm [114]
3 years ago
15

Three inches of snow fell on Monday. Five inches of snow fell on Tuesday. One-half inch of snow fell on Wednesday. How much snow

fell during these three days? Show your work in the space below. Don't forget to label the units on your answer.​
Mathematics
1 answer:
stiv31 [10]3 years ago
3 0

Answer:

9 and a half

Step-by-step explanation:

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−<br> 3<br> (<br> 7<br> −<br> 2<br> x<br> )<br> =<br> −<br> 1<br> −<br> 4<br> x
Bogdan [553]

Answer:

5208

Step-by-step explanation:

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2 years ago
What is the length of the rectangle?
gregori [183]

Step-by-step explanation:

area \: of \: rectangle \:  = 60 \:  {yards}^{2}  \\  \therefore \: (w + 4) \times \: w = 60\\  \\  \therefore \:  {w}^{2}  + 4w -60 = 0 \\  \\  \therefore \: {w}^{2}  + 10w - 6w -60 = 0 \\  \\   \therefore \: w({w} + 10) - 6(w  + 10)= 0 \\  \\  \therefore \: ({w} + 10) (w- 6)= 0 \\ \therefore \: {w} + 10 = 0 \: or \: w- 6 = 0 \\  \therefore \: {w}   = -  10  \: or \: w =  6  \\  \because \: sides \: of \: rectangle \: cant \: be \: negative \\  \therefore \: w \neq \:    - 10 \\  \\ \therefore \: w = 6 \\  \\ \therefore \: w + 4 = 6 + 4 = 10 \\  \\ length \: of \: rectangle \:  = 10 \: yards.

4 0
3 years ago
Tomika heard that the diagonals of a rhombus are perpendicular to each other. Help her test her conjecture. Graph quadrilateral
Stella [2.4K]

Answer:

a. The four sides of the quadrilateral ABCD are equal, therefore, ABCD is a rhombus

b. The equation of the diagonal line AC is y = 5 - x

The equation of the diagonal line BD is y = 5 - x

c. The diagonal lines AC and BD of the quadrilateral ABCD are perpendicular to each other

Step-by-step explanation:

The vertices of the given quadrilateral are;

A(1, 4), B(6, 6), C(4, 1) and D(-1, -1)

a. The length, l, of the sides of the given quadrilateral are given as follows;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

The length of side AB, with A = (1, 4) and B = (6, 6) gives;

l_{AB} = \sqrt{\left (6-4  \right )^{2}+\left (6-1  \right )^{2}} = \sqrt{29}

The length of side BC, with B = (6, 6) and C = (4, 1) gives;

l_{BC} = \sqrt{\left (1-6  \right )^{2}+\left (4-6  \right )^{2}} = \sqrt{29}

The length of side CD, with C = (4, 1) and D = (-1, -1) gives;

l_{CD} = \sqrt{\left (-1-1  \right )^{2}+\left (-1-4  \right )^{2}} = \sqrt{29}

The length of side DA, with D = (-1, -1) and A = (1,4)   gives;

l_{DA} = \sqrt{\left (4-(-1)  \right )^{2}+\left (1-(-1)  \right )^{2}} = \sqrt{29}

Therefore, each of the lengths of the sides of the quadrilateral ABCD are equal to √(29), and the quadrilateral ABCD is a rhombus

b. The diagonals are AC and BD

The slope, m, of AC is given by the formula for the slope of a straight line as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Therefore;

Slope, \, m_{AC} =\dfrac{1-4}{4-1} = -1

The equation of the diagonal AC in point and slope form is given as follows;

y - 4 = -1×(x - 1)

y = -x + 1 + 4

The equation of the diagonal AC is y = 5 - x

Slope, \, m_{BD} =\dfrac{-1-6}{-1-6} = 1

The equation of the diagonal BD in point and slope form is given as follows;

y - 6 = 1×(x - 6)

y = x - 6 + 6 = x

The equation of the diagonal BD is y = x

c. Comparing the lines AC and BD with equations, y = 5 - x and y = x, which are straight line equations of the form y = m·x + c, where m = the slope and c = the x intercept, we have;

The slope m for the diagonal AC = -1 and the slope m for the diagonal BD = 1, therefore, the slopes are opposite signs

The point of intersection of the two diagonals is given as follows;

5 - x = x

∴ x = 5/2 = 2.5

y = x = 2.5

The lines intersect at (2.5, 2.5), given that the slopes, m₁ = -1 and m₂ = 1 of the diagonals lines satisfy the condition for perpendicular lines m₁ = -1/m₂, therefore, the diagonals are perpendicular.

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Svetllana [295]
This is indeed a linear equation. y-4x=9 in standard form is y=4x+9.
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It would be $84.15 for the tablet and $12.75 for the memory card, so $14.85 off on the tablet and $2.25 off on the card. I hope this helps!
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