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2 years ago

HELPPP!!!! Which statement correctly describes the lines shown on the graph?

Mathematics

2 answers:

ladessa [460]2 years ago

5 0

Answer:I'm pretty sure its D

Step-by-step explanation:

vitfil [10]2 years ago

3 0

Answer:

I believe the answer is either B or C not A

Step-by-step explanation:

look at where its coming from

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Find the inverse of this matrix.<br> 1 -1 -1<br> -1 2 3 <br> 1 1 4

zheka24 [161]

Let's use Gaussian elimination. Consider the augmented matrix,

$\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\-1 & 2 & 3 & 0 & 1 & 0\\1 & 1 & 4 & 0 & 0 & 1\end{array}\right]$

• Add row 1 to row 2, and add -1 (row 1) to row 3:

$\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 2 & 5 & -1 & 0 & 1\end{array}\right]$

• Add -2 (row 2) to row 3:

$\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]$

• Add -2 (row 3) to row 2:

$\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]$

• Add row 2 and row 3 to row 1:

$\left[\begin{array}{ccc|ccc}1 & 0 & 0 & 5 & 3 & -1\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]$

So the inverse is

$\begin{bmatrix}1&-1&-1\\-1&2&3\\1&1&4\end{bmatrix}^{-1} = \boxed{\begin{bmatrix}5&3&-1\\7&5&-2\\-3&-2&1\end{bmatrix}}$

3 0

2 years ago

Find the equation of the line.

larisa [96]

-12 I just did this question In class

8 0

2 years ago

Find an equation of the line that passes through the points (-5, -3) and (3, 1)

Mkey [24]

$\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{-3})\quad (\stackrel{x_2}{3}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{(-3)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-5)}}}\implies \cfrac{1+3}{3+5}\implies \cfrac{4}{8}\implies \cfrac{1}{2}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{\cfrac{1}{2}}[x-\stackrel{x_1}{(-5)}]\implies y+3=\cfrac{1}{2}(x+5) \\\\\\ y+3=\cfrac{1}{2}x+\cfrac{5}{2}\implies y=\cfrac{1}{2}x+\cfrac{5}{2}-3\implies y = \cfrac{1}{2}x-\cfrac{1}{2}$

6 0

2 years ago

Read 2 more answers

12+3y+y=?<br> What is the answer?

puteri [66]

Answer:

12+4y

Step-by-step explanation:

12+3y+y=12+4y

3 0

2 years ago

Read 2 more answers

The level of the tide in a harbor changed from 9 1/4 ft to 4 1/2 ft above sea level over a period of 3 1/4 hr

kumpel [21]

Answer:

The answer is " $\bold{- \frac{19}{13} \ / hour}$ "

Step-by-step explanation:

Please find the complete question in the attached file.

Calculating the difference of $9 \frac{1}{4}\ and \ 4 \frac{1}{2}$ dividing the value by $3 \frac{1}{4}$

$\to 4 \frac{1}{2} - 9 \frac{1}{4}\\\\ \to \frac{9}{2} - \frac{37}{4}\\\\ \to \frac{18-37}{4} \\\\ \to -\frac{19}{4}\\\\\to -\frac{19}{4} \div \frac{13}{4}= -\frac{19}{4} \times \frac{4}{13} = -\frac{19}{13}\\$

3 0

2 years ago