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3 years ago

1. Round 47.38 to the nearest tenth.

Mathematics

2 answers:

Mashcka [7]3 years ago

8 0

Answer:

1. 47.4

2. 6

3. 18.57

4. 114.9

5. 75.01

attashe74 [19]3 years ago

6 0

Answer:

1. 47.38

2. 6

3. 18.57

4. 114.9

5. 75.01

Step-by-step explanation:

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Given this figure on a coordinate plane, determine which of the following statements

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Answer is D. Show that AC and BC bisect each other and meet at the same point

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3 years ago

The area of the yard was 6,756 square yards. The width of the yard was 12 yards. What was the length of the yard?

Igoryamba

<h2>The length of the yard was 563 yards.</h2>

Step-by-step explanation:

Given,

The area of the yard = 6,756 square yards and

The width of the yard (b) = 12 yards

To find, the length of the yard (l) = ?

We know that,

Area of the rectangle = Length(l) × Breadth(b)

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4 years ago

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Antonio has a total of 55 marbles. He has 15 green marbles and 12 red marbles. The rest of the marbles are blue. How many blue m

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3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

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3 years ago