All categories

3 years ago

Solve for X: -7x -1 = -9x -17

Mathematics

1 answer:

andre [41]3 years ago

6 0

Answer:

-8.

Step-by-step explanation:

-7x - 1 = -9x - 17

-7x - (-9x) = -17 - (-1)

-7x + 9x = -17 + 1

2x = -16

x = -8.

You might be interested in

At an ocean depth of 8 meters, a buoy bobs up and then down 5 meters from the ocean's depth. Sixteen seconds pass from the time

lisov135 [29]

Answer:

See attached for a graph

Step-by-step explanation:

We're going to plot sea level as y=0 and a depth of 8 meters as y=-8.

The problem statement tells you the initial point (x=0) is at normal ocean depth (y=-8), so the first point you put into your sine tool is ...

(x, y) = (0, -8)

The buoy takes 16 seconds to go from a high point to a low point, so the time to the first high point is half that, or x=8 seconds. That high point is 5 meters above its average depth, so is at y=-3.

The second point you will put into your sine tool is ...

(x, y) = (8, -3)

7 0

3 years ago

What should you do when you can’t sleep

zubka84 [21]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A fencing company charges $22 per foot to install a wood fence. How much will it cost to install a wood fence around a rectangul

borishaifa [10]

20+20+38+38=116

116×22 = 2552

It will cost $2,552 to install the wood fence.

4 0

3 years ago

Give an example of an equation that is a linear function. Explain why is is a linear

maxonik [38]

Answer:

For example, a common equation, y=mx+b y = m x + b

Step-by-step explanation:

is a linear function because it meets both criteria with x and y as variables and m and b as constants.

4 0

2 years ago

If 47400 dollars is invested at an interest rate of 7 percent per year, find the value of the investment at the end of 5 years f

Anni [7]

Answer:

Part A) Annual $\$66,480.95$

Part B) Semiannual $\$66,862.38$

Part C) Monthly $\$67,195.44$

Part D) Daily $\$67,261.54$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part A) Annual

in this problem we have

$t=5\ years\\ P=\$47,400\\ r=0.07\\n=1$

substitute in the formula above

$A=\$47,400(1+\frac{0.07}{1})^{1*5}$

$A=\$47,400(1.07)^{5}$

$A=\$66,480.95$

Part B) Semiannual

in this problem we have

$t=5\ years\\ P=\$47,400\\ r=0.07\\n=2$

substitute in the formula above

$A=\$47,400(1+\frac{0.07}{2})^{2*5}$

$A=\$47,400(1.035)^{10}$

$A=\$66,862.38$

Part C) Monthly

in this problem we have

$t=5\ years\\ P=\$47,400\\ r=0.07\\n=12$

substitute in the formula above

$A=\$47,400(1+\frac{0.07}{12})^{12*5}$

$A=\$47,400(1.0058)^{60}$

$A=\$67,195.44$

Part D) Daily

in this problem we have

$t=5\ years\\ P=\$47,400\\ r=0.07\\n=365$

substitute in the formula above

$A=\$47,400(1+\frac{0.07}{365})^{365*5}$

$A=\$47,400(1.0002)^{1,825}$

$A=\$67,261.54$

8 0

3 years ago