A bag of tiles contains 6 green 4 yellow and 5 blue tiles. If one tile is pulled at random what is the probability of NOT choosi
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The probability that this bag will be warm enough on a randomly
selected May night at the park is 0.8106 ⇒ answer C
Step-by-step explanation:
You are planning a May camping trip to Denali National Park in Alaska
and want to make sure your sleeping bag is warm enough.
The average low temperature in the park for May follows a normal
distribution
The given is:
1. The mean is 32°F
2. The standard deviation is 8°F
3. One sleeping bag you are considering advertises that it is good for
temperatures down to 25°F (x ≥ 25)
At first let us find the z-score
∵ z = (x - μ)/σ, where x is the score, μ is the mean, σ is standard deviation
∵ μ = 32°F , σ = 8°F , x = 25°F
- Substitute these values in the rule
∴ z =
Now let us find the corresponding area of z-score in the normal
distribution table
∵ The corresponding area of z = -0.875 is 0.18943
∵ For P(x ≥ 25) the area to the right is needed
∵ P(x ≥ 25) = 1 - 0.18943 = 0.8106
∴ P(x ≥ 25) = 0.8106
The probability that this bag will be warm enough on a randomly
selected May night at the park is 0.8106
Learn more:
You can learn more about mean and standard deviation in brainly.com/question/6073431
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ANSWER
The total length of the trip to and from work in August is
EXPLANATION
The total length of the trip to and from work is
If Jonah worked 21 days in August,
Then, the total length of the trip to and from work is
Change the decimal to fraction and multiply,
Convert back to decimal
The total length of the trip to and from work in August is
EXPLANATION
The total length of the trip to and from work is
If Jonah worked 21 days in August,
Then, the total length of the trip to and from work is
Change the decimal to fraction and multiply,
Convert back to decimal