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2 years ago

The midpoint of x and m is a, what is x?

Mathematics

1 answer:

Harlamova29_29 [7]2 years ago

7 0

Answer:

Step-by-step explanation:

if you are questioning from the Co-ordinate geometry chapter then you should equal the section formula between them like

if the coordinate of point m is = (x,y) and for a is (x₁ , y₁) and for point x is ( x₃ , y₃)

then, from this we can find the value of X(x3 , y3)

if we have the coordinates of point m.

Step-by-step explanation:

hope it helps mate

please mark as brainliest

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What is the slope of the line represented by the equation y+3=-4(x-5)

jekas [21]

Correct choice is, D. 4

7 0

3 years ago

Read 2 more answers

0.75(2 + 6 x 4 - 2 x 7 - 2) A. 1 B. 5.25 C. 8.5 D. 22.5

Alekssandra [29.7K]

Hey there!

ORIGINAL EQUATION:
0.75(2 + 6 x 4 - 2 × 7 - 2)

WORKING WITHIN the PARENTHESES:
2 + 6 x 4 - 2 × 7 - 2

= 2 + 24 - 2 × 7 - 2

= 26 - 2 × 7 - 2

= 26 - 14 - 2

= 12 - 2

= 10

NEW EQUATION:

0.75(10)

SIMPLIFY IT!
7.50 ≈ 7.5

Therefore, your answer should be: 7.5

~Amphitrite1040:)

5 0

2 years ago

Find

Westkost [7]

Answer:

dy/dx = -b/a cot α

Step-by-step explanation:

x² / a² + y² / b² = 1

Take derivative with respect to x.

2x / a² + 2y / b² dy/dx = 0

2y / b² dy/dx = -2x / a²

dy/dx = -b²x / (a²y)

Substitute:

dy/dx = -b²a cos α / (a²b sin α)

dy/dx = -b cos α / (a sin α)

dy/dx = -b/a cot α

8 0

3 years ago

If a toy truck is created in a 2:9 scale, and the wheel of the toy is 14cm wide, how wide is the actual wheel?

lesya [120]

Answer:63 cm

Step-by-step explanation:

Given

The scale of creation is 2:9

The width of the toy wheel is 14 cm

Suppose x is the actual width of the truck

$\therefore \dfrac{2}{9}=\dfrac{14}{x}\\\\\Rightarrow x=\dfrac{9}{2}\times 14=63\ cm$

Thus, the width of actual truck is 63 cm

8 0

2 years ago

Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar

Brrunno [24]

The distance between the two points is $d=8.6m$

The polar coordinate of A is $\left(4.47,296.57\right)$

The polar coordinate of B is $\left(4.24,135\right)$

Explanation:

The two points are $A(2,-4)$ and $B(-3,3)$

The distance between two points is given by,

$d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6$

Thus, the distance between the two points is $d=8.6m$

The polar coordinates of A can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $A(2,-4)$ , we get,

Distance = $\sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43$

To make the angle positive, let us add 360,

$\theta=360-63.43=296.57$

The polar coordinate of A is $\left(4.47,296.57\right)$

Similarly, The polar coordinate of B can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $B(-3,3)$ , we get,

Distance = $\sqrt{(3)^{2}+(3)^{2}}=4.24$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45$

To make the angle positive, let us add 360,

$\theta=180-45=135^{\circ}$

The polar coordinate of B is $\left(4.24,135\right)$

5 0

3 years ago