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Alex17521 [72]
2 years ago
10

Hi! Could you help me?? I’m stuck on this one

Mathematics
2 answers:
lutik1710 [3]2 years ago
7 0

Answer:

32 black grapes

Step-by-step explanation:

the 3 part of the ratio represents 24 green grapes , then

24 ÷ 3 = 8 ← value of 1 part of the ratio, then

black grapes = 4 × 8 = 32

BlackZzzverrR [31]2 years ago
4 0
3:4
Times by 8 both sides
24:32
32 black grapes
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5h+3 - j; use h = 6, and j = 1
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Answer:

32

Step-by-step explanation:

lets substitute the appropriate values in the equation:

5h+3 - j    h= 6    j=1 , so we have:

5*6 +3 -1

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Find all solutions of each equation on the interval 0 ≤ x &lt; 2π.
Korvikt [17]

Answer:

x = 0 or x = \pi.

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}.

\displaystyle \sec{x} = \frac{1}{\cos{x}}.

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, \sin^{2}{x} = 1 - \cos^{2}{x}. Therefore, for the square of tangents,

\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}.

This equation will thus become:

\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2.

To simplify the calculations, replace all \cos^{2}{x} with another variable. For example, let u = \cos^{2}{x}. Keep in mind that 0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1.

\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2.

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Solve this equation for u:

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