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storchak [24]
3 years ago
7

Solve for c in the literal equation 9p + 7c = p. Represent any fractions in reduced proper or improper form only.

Mathematics
1 answer:
Marina CMI [18]3 years ago
6 0

Answer:

-8/7p=c

Step-by-step explanation:

add 9p to both sides of the equation

then divide both sides by 7

tah dah

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1: multiple both sides by 2
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Answer is 6 and the process is elimination!
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Answer:

a

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Jessica jogs on a path that is 25 km long to get to a park that is south of the jogging path. If it takes Jessica 2.5 hours then
GalinKa [24]
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6 0
3 years ago
Read 2 more answers

zhuklara [117]

Step-by-step answer:

Given:

A triangle

Perimeter  = 60 cm

longest side = 4* shortest side (x)

Solution:

longest side = 4x

shortest side = x

third (intermediate side = 60 -x -4x = 60-5x

The triangle inequality specifies that the sum of the two shorter sides must be greater than the longest side to form a triangle.  Hence

x + y > 4x

x + 60-5x > 4x

60 - 4x > 4x

8x < 60

x < 60/8 = 7.5, or

x < 7.5

Therefore to form a triangle, x (shortest side) must be less than 7.5 cm.

Examine the options: both 7 and 5 are both less than 7.5 cm.

40, 30 and 25 all have a problem because the longest side (4 times longer) will exceed the perimeter of 60.

Now also examine cases where 4x is NOT the longest side, in which case we need

4x>=y

or

4x >= 60-5x

9x >=60

x >= 6.67

so x=5 will not qualify, because 4x will no longer be the longest side.

The only valid option is x=7 cm

The side lengths for x=7 and x=5 are, respectively,

(7, 25, 28)

5, 20, 35  (in which case, the longest side is no longer 4x=20, so eliminated)

7 0
3 years ago
Easy question.<br><br> Solve the inequality -5x&lt;40
laiz [17]

\huge\text{Hey there!}

\mathsf{-5x < 40}

\large\text{DIVIDE -5 to BOTH SIDES}

\mathsf{\dfrac{-5x}{-5}

\rm{CANCEL\  out: \dfrac{-5}{-5} \ because\  that \ gives\  you\  1}

\rm{KEEP: \dfrac{40}{-5}\ because \ that \ gives \  you \ what \ you \ are\ comparing}\\\\\rm{to \ the \ x-value}

\mathsf{\dfrac{40}{-5}=\boxed{\bf -8}}

\mathsf{x > -8}

\boxed{\boxed{\large\textsf{Answer: \large \bf x }\bf  > \large\textsf{\bf -8}}}\huge\checkmark

\boxed{\large\textsf{IT is an O(P)(E)(N)(E)(D)   circle shaded to the right}}

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

3 0
3 years ago
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