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MrRissso [65]
3 years ago
9

What is the perimeter of STU?

Mathematics
1 answer:
belka [17]3 years ago
7 0

Answer:

2x x. – 1) 2x2 + x - 3 - (2x2 – 2x)2x x. – 1) 2x2 + x - 3 - (2x2 – 2x)2x x. – 1) 2x2 + xx x. – 1) 2x2 + x - 3 - (2x2 – 2x)2x x. – 1) 2x2 + x - 3 - (2x2 – 2x)2x x. – 1) 2x2 + x - 3 - (2x2 – 2x)2x x. – 1) 2x2 + x - 3 - (2x2 – 2x)2x x. – 1) 2x2 + x - 3 - (2x2 – 2x)2x x. – 1) 2x2 + x - 3 - (2x2 – 2x)2x x. – 1) 2x2 + x - 3 - (2x2 – 2x)2x x. – 1) 2x2 + x - 3 - (2x2 – 2x)2x x. – 1) 2x2 + x - 3 - (2x2 – 2x)2x x. – 1) 2x2 + x - 3 - (2x2 – 2x)2x x. – 1) 2x2 + x - 3 - (2x2 – 2x)2x x. – 1) 2x2 + x - 3 - (2x2 – 2x)2x x. – 1) 2x2 + x - 3 - (2x2 – 2x)

Step-by-step explanation:

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Find the value of (6^0 − 7^0) × (6^0 + 7^0)
uysha [10]

Answer:

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Beth is going to enclose a rectangular area in back of her house. the house wall will form one of the four sides of the fenced i
Alina [70]

The maximum possible area would have a length of 24 feet and width of 12 feet.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depend on other variables while a dependent variable is a variable that depends on other variables.

Let x represent the length and y represent the width, hence:

Since beth has 48 ft fencing and cover 3 sides, hence:

x + 2y = 48  

x = 48 - 2y     (1)

Also:

Area (A) = xy

A = (48 - 2y)y

A = 48y - 2y²

The maximum area is at A' = 0, hence:

A' = 48 - 4y

48 - 4y = 0

y = 12 feet

x = 48 - 2(12) = 24

The maximum possible area would have a length of 24 feet and width of 12 feet.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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2 years ago
Can someone help me this question please?
pashok25 [27]
Larger number is 32 because if u take 48 minus 16 u get your anwser
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